JAVA入门基础--数据类型

数学中,没有办法用十进制来精确表达1/3.

同样的,计算机中,没有办法用二进制表示0.1

比如:python中,java中 都是一样的。

>>> a=6.0
>>> b=4.9
>>> a-b
1.0999999999999996
>>> x=3.0
>>> y=2.9
>>> x-y
0.10000000000000009
>>> (x-y)>0.1
True

>>> (x-y)==0.1
False
>>>

  在上述代码中: a-b 的值会无限接近于1.1。 x-y 的值会无限接近0.1。

 

 1 package day02;
 2 
 3 import java.util.Scanner;
 4 
 5 public class inp_demo {
 6 
 7     public static void main(String[] args) {
 8         // TODO Auto-generated method stub
 9         Scanner scanner=new Scanner(System.in);
10         String name=scanner.next();
11         System.out.println(name);
12                 
13     }
14 
15 }

 

数据类型的练习:

 1 package day02;
 2 
 3 import java.util.Scanner;
 4 
 5 public class inp_demo {
 6 
 7     public static void main(String[] args) {
 8         // TODO Auto-generated method stub
 9 //        Scanner scanner=new Scanner(System.in);
10 //        String name=scanner.next();
11 //        System.out.println(name);
12         int a=250;
13         //int b=100000000000;
14         System.out.println(5/2);
15         System.out.println(2/5);
16         int c=2147483647;
17         System.out.println(c+1);
18         
19         //long d=10000000000;
20         long e=10000000000L;
21         long f=1000000000*2*10L;
22         System.out.println("f:"+f);
23         long g=1000000000*3*10L;
24         System.out.println("g>>>"+g);
25         long h=1000000000L*3*10;
26         System.out.println("e>>>"+h);
27         long i;
28         i=System.currentTimeMillis();
29         System.out.println("time:"+i);
30         
31         
32         float j=3.14f;
33         float k,l;
34         k=6.0f;
35         l=4.9f;
36         System.out.println(k-l);
37                 
38     }
39 
40 }

 结果:

2
0
-2147483648
f:20000000000
g>>>-12949672960
e>>>30000000000
time:1535892324164
1.0999999

 

 

 1 package day02;
 2 
 3 import java.util.Scanner;
 4 
 5 public class inp_demo {
 6 
 7     public static void main(String[] args) {
 8         // TODO Auto-generated method stub
 9         
10 //        //布尔类型,占一个字节。
11 //        boolean b1=true;
12 //        boolean b2=false;
13         //字符类型,占有两个字节  java的字符编码表是unicode
14         char o3='m';
15         char o4=' ';
16         char o5=65515;//0~65535
17         System.out.println(o5);
18         char o='中';
19         System.out.println(o);
20         
21         char o1='\u4e2d';
22         System.out.println(o1);
23         
24         char o2=65;
25         System.out.println(o2);
26         
27         System.out.println("(2+2):"+(2+2));
28         System.out.println('2'+'2');
29         
30         System.out.println("char2》\t》》\n》"+'2');
31         
32         
33         
34         
35         
36         
37         
38         
39         
40         
41 //        Scanner scanner=new Scanner(System.in);
42 //        String name=scanner.next();
43 //        System.out.println(name);
44         /*
45         int a=250;
46         //int b=100000000000;
47         System.out.println(5/2);
48         System.out.println(2/5);
49         int c=2147483647;
50         System.out.println(c+1);
51         
52         //long d=10000000000;
53         long e=10000000000L;
54         long f=1000000000*2*10L;
55         System.out.println("f:"+f);
56         long g=1000000000*3*10L;
57         System.out.println("g>>>"+g);
58         long h=1000000000L*3*10;
59         System.out.println("e>>>"+h);
60         long i;
61         i=System.currentTimeMillis();
62         System.out.println("time:"+i);
63         
64         
65         float j=3.14f;
66         float k,l;
67         k=6.0f;
68         l=4.9f;
69         System.out.println(k-l);
70         */
71                 
72     }
73 
74 }
练习

 

//类型强制转换.从小到大,系统自动转换,从大到小,需要强制转换,强转可能会导致进度丢失,或是溢出
		int age=20;
		long age_l=(long)age;
		System.out.println(age_l);
		
		
		long d=5;//int type into long type
		double e=5;//int type into double type
		double f=3.14f;//float type into double type
		
		double h=25.987;
		int i=(int)h;
		System.out.println(i);//print>>> 25 

  

posted @ 2018-09-02 19:07  巨兽~墨菲特  阅读(127)  评论(0编辑  收藏  举报