oracle课堂随笔--第十一天
排序:
SQL> select last_name, salary from employees order by salary;
SQL> select last_name, salary from employees order by salary desc;大到小
SQL> select last_name, salary from employees order by last_name;
SQL> select last_name, hire_date from employees order by hire_date;
SQL> select last_name, salary, commission_pct from employees order by salary desc, commission_pct desc;
SQL> select last_name, salary*12*(1+commission_pct) from employees order by 2;
SQL> select last_name, salary*12*(1+commission_pct) total_salary from employees order by total_salary;
单行函数
SQL> select upper(first_name), lower(last_name), length(last_name) from employees;
SQL> select (sysdate-hire_date)/7 from employees;
SQL> select trunc((sysdate-hire_date)/30, 0) from employees;
SQL> select trunc(months_between(sysdate,hire_date), 0) from employees;
SQL> select sysdate+3650 from dual;
SQL> select add_months(sysdate, 120) from dual;
SQL> select next_day('2015-09-01', 'friday') from dual;
SQL> select next_day('2015-10-01', 6) from dual;
SQL> select last_day(sysdate) from dual;
SQL> select round(to_date('2015-10-10','yyyy-mm-dd'), 'MONTH') from dual;
SQL> select round(to_date('2015-10-16','yyyy-mm-dd'), 'MONTH') from dual;
SQL> select round(to_date('2015-10-10','yyyy-mm-dd'), 'YEAR') from dual;
SQL> select round(sysdate, 'DAY') from dual;
类型转换和其他函,数
转换 to_char
SQL> select to_char(salary, '$999,999.00') from employees;
SQL> select last_name, to_char(hire_date, 'dd-Mon-RR') from employees;
SQL> select to_char(sysdate, 'yyyy-mm-dd hh24:mi:ss') from dual;
SQL> select to_char(sysdate, 'yyyy-mm-dd hh:mi:ss AM') from dual;
SQL> select last_name from employees where hire_date=to_date('2006-05-23', 'yyyy-mm-dd');
SQL> select to_number('$123,456.78', '$999,999.00') from dual;
一
elect last_name, job_id, salary,
case job_id
when 'IT_PROG' then salary+1000
when 'SA_REP' then salary+1500
when 'ST_CLERK' then salary+2000
else salary
end new_salary
from employees;
二
select last_name, job_id, salary,
decode( job_id,
'IT_PROG', salary+1000,
'SA_REP', salary+1500,
'ST_CLERK', salary+2000,
salary) new_salary
from employees;