[SoapUI] 将科学计数法转化为普通数字，并且只保留小数点后几位

方案一：

import java.text.NumberFormat
class CompareHashMap {
 
    def regEx_Numeric = '-?[1-9]\\d*$|-?([1-9]\\d*\\.\\d*|0\\.\\d*|0?\\.0+|0)$'
    def regEx_ScientificNotation = '^((-?\\d+.?\\d*)[Ee]{1}(-?\\d+))$'   //科学计数法正则表达式
    int decimalPrecision = 5  //Compare 5 decimal places
 
    CompareHashMap(){
    }
 
    def formatDecimalPrecision(def dataValue){
    NumberFormat format = NumberFormat.getNumberInstance()
    format.setMaximumFractionDigits(decimalPrecision)
         
    dataValue = dataValue.toString()
         
    if(dataValue.matches(regEx_ScientificNotation)){
    　　BigDecimal db = new BigDecimal(dataValue)
    　　dataValue = db.toPlainString()
    }
         
    if(dataValue.matches(regEx_Numeric)){
    　　//Switch String to double firstly
    　　dataValue = Double.parseDouble(dataValue)  
    　　dataValue = format.format(dataValue)
    }
    return dataValue
　　}
}

方案二：

def formatDecimalPrecision(def dataValue, int decimalPrecision){   
　　    
      NumberFormat format = NumberFormat.getNumberInstance()
      format.setMaximumFractionDigits(decimalPrecision)
         
      dataValue = dataValue.toString()
      if(dataValue.isBigDecimal()){
           dataValue = new BigDecimal(dataValue).toPlainString()
       }
         
      def regEx_Numeric = '-?[1-9]\\d*$|-?([1-9]\\d*\\.\\d*|0\\.\\d*|0?\\.0+|0)$'    
      if(dataValue.matches(regEx_Numeric)){
            //Switch String to double firstly
            dataValue = Double.parseDouble(dataValue)
            dataValue = format.format(dataValue)
       }
         
      return dataValue
}