【codeforces 765F】 Souvenirs
http://codeforces.com/problemset/problem/765/F (题目链接)
题意
给出$n$个数的序列,$m$次询问,每次查询区间$[l,r]$之间相差最小的两个数的差。
Solution
迷,右转题解→_→:jump
奇怪的线段树
细节
不造
代码
// codeforces 765F #include<algorithm> #include<iostream> #include<cstdlib> #include<cstring> #include<cstdio> #include<vector> #include<cmath> #include<ctime> #define LL long long #define inf 2147483640 #define Pi acos(-1.0) #define free(a) freopen(a".in","r",stdin),freopen(a".out","w",stdout) using namespace std; const int maxn=300010; int n,Q,ans,a[maxn],res[maxn]; struct data {int l,r,id;}q[maxn]; struct node {int l,r,s;vector<int> v;}tr[maxn<<2]; bool cmp(data a,data b) {return a.r<b.r;} void build(int k,int s,int t) { tr[k].l=s;tr[k].r=t;tr[k].s=inf; if (s==t) {tr[k].v.push_back(a[s]);return;} int mid=(s+t)>>1; build(k<<1,s,mid);build(k<<1|1,mid+1,t); int i=0,j=0,ll=tr[k<<1].v.size(),rr=tr[k<<1|1].v.size(); while (i<ll || j<rr) { if ((i<ll && tr[k<<1].v[i]<tr[k<<1|1].v[j]) || j==rr) tr[k].v.push_back(tr[k<<1].v[i++]); else tr[k].v.push_back(tr[k<<1|1].v[j++]); } for (int i=1;i<=t-s;i++) tr[k].s=min(tr[k].s,tr[k].v[i]-tr[k].v[i-1]); } int query(int k,int s,int t) { int l=tr[k].l,r=tr[k].r,mid=(l+r)>>1; if (l==s && r==t) return tr[k].s; if (t<=mid) return query(k<<1,s,t); else if (s>mid) return query(k<<1|1,s,t); else return min(query(k<<1,s,mid),query(k<<1|1,mid+1,t)); } void modify(int k,int p,int val) { int l=tr[k].l,r=tr[k].r,mid=(l+r)>>1; if (l==r) {tr[k].s=min(tr[k].s,abs(val-tr[k].v[0]));ans=min(ans,tr[k].s);return;} vector<int>::iterator t=lower_bound(tr[k].v.begin(),tr[k].v.end(),val); if (t==tr[k].v.end() || *t-val>=ans) if (t==tr[k].v.begin() || val-*--t>=ans) {ans=min(ans,tr[k].s);return;} if (p<=mid) modify(k<<1,p,val); else modify(k<<1|1,p,val),modify(k<<1,p,val); tr[k].s=min(tr[k].s,min(tr[k<<1].s,tr[k<<1|1].s)); } int main() { scanf("%d",&n); for (int i=1;i<=n;i++) scanf("%d",&a[i]); scanf("%d",&Q); for (int i=1;i<=Q;i++) scanf("%d%d",&q[i].l,&q[i].r),q[i].id=i; sort(q+1,q+1+Q,cmp); build(1,1,n); int p=1; for (int i=1;i<=Q;i++) { while (p<q[i].r) ans=inf,modify(1,p,a[p+1]),p++; res[q[i].id]=query(1,q[i].l,q[i].r); } for (int i=1;i<=Q;i++) printf("%d\n",res[i]); return 0; }
This passage is made by MashiroSky.