【codevs1993】 草地排水
http://codevs.cn/problem/1993/ (题目链接)
题意
求有向图最大流。
Solution
Dinic。
代码
// codevs1993 #include<algorithm> #include<iostream> #include<cstring> #include<cstdlib> #include<cstdio> #include<cmath> #include<queue> #define LL long long #define inf 2147483640 #define MOD 10000 #define Pi acos(-1.0) #define free(a) freopen(a".in","r",stdin),freopen(a".out","w",stdout); using namespace std; const int maxn=210; struct edge {int to,next,w;}e[maxn<<1]; int d[maxn],head[maxn],cnt=1,ans,n,m; void link(int u,int v,int w) { e[++cnt]=(edge){v,head[u],w};head[u]=cnt; e[++cnt]=(edge){u,head[v],0};head[v]=cnt; } bool bfs() { memset(d,-1,sizeof(d)); queue<int> q;q.push(1);d[1]=0; while (!q.empty()) { int x=q.front();q.pop(); for (int i=head[x];i;i=e[i].next) if (e[i].w && d[e[i].to]<0) { d[e[i].to]=d[x]+1; q.push(e[i].to); } } return d[n]>0; } int dfs(int x,int f) { if (x==n || f==0) return f; int w,used=0; for (int i=head[x];i;i=e[i].next) if (e[i].w && d[e[i].to]==d[x]+1) { w=dfs(e[i].to,min(e[i].w,f-used)); used+=w; e[i].w-=w;e[i^1].w+=w; if (used==f) return used; } if (!used) d[x]=-1; return used; } void Dinic() { while (bfs()) ans+=dfs(1,inf); } int main() { scanf("%d%d",&m,&n); for (int u,v,w,i=1;i<=m;i++) { scanf("%d%d%d",&u,&v,&w); link(u,v,w); } Dinic(); printf("%d",ans); return 0; }
This passage is made by MashiroSky.