软件测试 作业3

/**

     * Finds and prints n prime integers

     * Jeff Offutt, Spring 2003

     */

 

 

    private static void printPrimes(int n) {

        int curPrime; //Value currently considered for primeness

        int numPrimes; // Number of primes found so far;

        boolean isPrime; //Is curPrime prime?int[] primes = new int[MAXPRIMES];// The list of primes.

        

        // Initialize 2 into the list of primes.

        primes[0] = 2;

        numPrimes = 1;

        curPrime = 2;

        while(numPrimes < n) {

            curPrime++; // next number to consider...

            isPrime = true;

            for(int i = 0; i <= numPrimes; i++ ) {

                //for each previous prime.

                if(isDvisible(primes[i],curPrime)) {

                    //Found a divisor, curPrime is not prime.

                    isPrime = false;

                    break;

                }

            }

            if(isPrime) {

                // save it!

                primes[numPrimes] = curPrime;

                numPrimes++;

            

            }

        }// End while

        

        // print all the primes out

        for(int i = 0; i < numPrimes; i++) {

            System.out.println("Prime: " + primes[i] );

 

        }

        

    }// End printPrimes.

 

 

(a) Draw the control flow graph for the printPrime() method.

 

 

 

(b) Consider test cases ti = (n = 3) and t2 = ( n = 5). Although these tour the same prime paths in printPrime(), they don't necessarily find

the same faults. Design a simple fault that t2 would be more likely to discover than t1 would.

 

 

while(numPrimes<n)改成(while(numPrimes<4)使其越界。

 

(c) For printPrime(), find a test case such that the corresponding test path visits the edge that connects the beginning of the while statement

to the for statement without going through the body of the while loop.

 

n=1

(d) Enumerate the test requirements for node coverage, edge coverage,and prime path coverage for the path for printPrimes().

 

1:节点覆盖:TR={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15}

2:边覆盖:TR={12),(23),(34),(45),(56),(67),(57),(74),(78),(89),(79),(92),(915),(210),(1011),(1012),(1113),(1214),(1314),(1415}

,

3:主路径覆盖:TR={[4,5,7,4],[5,7,4,5],[7,4,5,7],[4,5,6,7,4],

[5,6,7,4,5],[7,4,5,6,7],[6,7,4,5,6],[2,3,4,5,6,7,8,9,2],[2,3,4,5,6,7,9,2],[2,3,4,5,7,8,9,2],[2,3,4,5,7,9,2],[3,4,5,6,7,8,9,2,3],[3,4,5,6,7,9,2,3],[3,4,5,7,8,9,2,3],[3,4,5,7,9,2,3],[4,5,6,7,8,9,2,3,4],[4,5,6,7,9,2,3,4],

[4,5,7,8,9,2,3,4],[4,5,7,9,2,3,4],[5,6,7,8,9,2,3,4,5],[5,7,8,9,2,3,4,5],[5,6,7,9,2,3,4,5],[5,7,9,2,3,4,5],[6,7,8,9,2,3,4,5,6],[6,7,9,2,3,4,5,6],

[7,8,9,2,3,4,5,6,7],[7,9,2,3,4,5,6,7],[7,8,9,2,3,4,5,7],[7,9,2,3,4,5,7],

[8,9,2,3,4,5,6,7,8],[8,9,2,3,4,5,7,8],[9,2,3,4,5,6,7,8,9],[9,2,3,4,5,7,8,9],[9,2,3,4,5,7,9],[9,2,3,4,5,7,9][1,2,3,4,5,6,7,8,9,15],

[1,2,3,4,5,7,8,9,15],[1,2,3,4,5,6,7,9,15],[1,2,3,4,5,7,9,15],

[1,2,10,11,12,14,15],

[1,2,10,11,13,14,15],

做覆盖测试

 

posted @ 2018-03-26 21:07  BaiMaSangBu  阅读(95)  评论(0编辑  收藏  举报