EasyUi DataGrid 获取选中行的checkbox
EasyUi DataGrid 获取选中行的checkbox
var checked = $(":checkbox[name=ID]:checked"); console.log(checked); var IDS = new Array(); $.each(checked, function (i, v) { IDS[i] = v.value; });
获取行的内容
var row = $('#jgrid').datagrid('getSelected');