第二次作业_201731062533
2019-03-28 19:44 MarkarovZ 阅读(152) 评论(1) 编辑 收藏 举报GIT地址 | https://github.com/MarkarovZ |
GIT用户名 | MarkarovZ |
学号后五位 | 62533 |
博客地址 | https://www.cnblogs.com/MarkarovZ/ |
作业链接 | https://edu.cnblogs.com/campus/xnsy/SoftwareEngineeringClass2/homework/2795 |
一.配置开发环境
VS在刚入学的时候就装好了,截图是重新打开Visual Studio Installer截取的,在安装VS的时候没有遇到问题。
二.代码设计
整个程序分成两个大模块:1.生成算式字符串2.计算算式的结果并验证该算式是否符合要求
1.
/// <summary> /// 生成算式 /// </summary> /// <param name="num">算式数量</param> void FormulaGeneration(int num) { string formula = ""; int n = 0; string str = ""; double ans = 0; for (int i = 0; i < num; i++) { n = random.Next(2, 4); do { str = FormulaCreation(n); formula = str + "!"; ans = operate(formula); if (ans % 1 == 0 && ans > 0 && flag == true) { break; } } while (true); formula = str + "=" + operate(formula); ; formulas.Add(formula); } } /// <summary> /// 生成算式字符串 /// </summary> /// <param name="n">运算符数量</param> /// <returns>算式字符串</returns> string FormulaCreation(int n) { int a, b, c, d, e; string x, y, z; switch (n) { case 2: a = random.Next(0, 101); b = random.Next(0, 101); c = random.Next(0, 101); d = random.Next(0, 4); x = Formula(d); d = random.Next(0, 4); y = Formula(d); return a + "" + x + "" + b + "" + y + "" + c; case 3: a = random.Next(0, 101); b = random.Next(0, 101); c = random.Next(0, 101); d = random.Next(0, 101); e = random.Next(0, 4); x = Formula(e); e = random.Next(0, 4); y = Formula(e); e = random.Next(0, 4); z = Formula(e); return a + "" + x + "" + b + "" + y + "" + c + "" + z + "" + d; } return ""; } /// <summary> /// 返回运算符 /// </summary> /// <param name="n">运算符类型</param> /// <returns>运算符</returns> string Formula(int n) { switch(n) { case 0: return "+"; case 1: return "-"; case 2: return "*"; case 3: return "/"; } return ""; }
2.
#region private bool judgenumber(string text)//判断是否为数字 { try { int var1 = Convert.ToInt32(text); return true; } catch { return false; } } private bool judgeoperator(string text)//判断是否为运算符 { if (text == "(" || text == ")" || text == "+" || text == "-" || text == "*" || text == "/") { return true; } else return false; } public object addition(object a, object b)//加法 { Decimal d1 = Decimal.Parse(a.ToString()); Decimal d2 = Decimal.Parse(b.ToString()); return d2 + d1; } public object subduction(object a, object b)//减法 { Decimal d1 = Decimal.Parse(a.ToString()); Decimal d2 = Decimal.Parse(b.ToString()); return d2 - d1; } public object multiplication(object a, object b)//乘法 { Decimal d1 = Decimal.Parse(a.ToString()); Decimal d2 = Decimal.Parse(b.ToString()); return d2 * d1; } public object division(object a, object b)//除法 { Decimal d1 = Decimal.Parse(a.ToString()); Decimal d2 = Decimal.Parse(b.ToString()); if(d2%d1!=0||d2<d1) { flag = false; return -10000; } else { flag = true; return d2 / d1; } } int judgelevel(string text)//判断优先级 { if (text.Equals("(")) { return 1; } else if (text.Equals(")") || text.Equals("(") || text.Equals(")")) { return 1; } else if (text.Equals("+") || text.Equals("-")) { return 2; } else if (text.Equals("*") || text.Equals("/")) { return 3; } else return 10; } int operator_dected(string types, string a, string b)//根据运算符的类型返回对应的值 { if (types == "+") { return Convert.ToInt32(addition(a, b)); } else if (types == "-") { return Convert.ToInt32(subduction(a, b)); } else if (types == "*") { return Convert.ToInt32(multiplication(a, b)); } else if (types == "/") { return Convert.ToInt32(division(a, b)); } else return 999; } double operate(string Str) { stack_number.Clear();//清空栈 stack_operator.Clear(); str = Str + "!";//!为结束运算符 int temp_count = 0; try { for (int i = 0; i < str.Length; i++) { substr = str.Substring(i, 1); if (judgenumber(substr))//如果是数字 { if (temp_count == 0) { stack_number.Push(substr); } else temp_count--; if (judgenumber(str.Substring(i + 1, 1))) { string link1 = stack_number.Pop(); link1 += str.Substring(i + 1, 1); stack_number.Push(link1); temp_count++; } } else if (judgeoperator(substr)) { if (stack_operator.Count >= 1) { int new1 = judgelevel(substr); int old1 = judgelevel(stack_operator.Peek()); if (old1 < new1 || substr == "(")//判断优先级 { stack_operator.Push(substr); //将运算符插入栈中 } else { if (substr == ")") { for (; stack_operator.Count > 0; stack_operator.Pop()) { if (stack_operator.Contains("(") && stack_operator.Peek() == "(") { stack_operator.Pop(); break; } else { int temp1 = Convert.ToInt32(stack_number.Peek()); stack_number.Pop(); int temp2 = Convert.ToInt32(stack_number.Peek()); stack_number.Pop(); stack_number.Push(operator_dected(stack_operator.Peek(), temp1.ToString(), temp2.ToString()).ToString()); } } } else { for (; stack_operator.Count > 0 && stack_number.Count >= 2 && stack_operator.Peek() != "("; stack_operator.Pop()) { string temp_a = substr; int new2 = judgelevel(temp_a); int old2 = judgelevel(stack_operator.Peek()); if (old2 < new2 || substr == "(")//判断优先级 { break; } else { int temp3 = Convert.ToInt32(stack_number.Peek()); stack_number.Pop(); int temp4 = Convert.ToInt32(stack_number.Peek()); stack_number.Pop(); stack_number.Push(operator_dected(stack_operator.Peek(), temp3.ToString(), temp4.ToString()).ToString()); } } stack_operator.Push(substr); } } } else { stack_operator.Push(substr); } } else if (substr == "!") { for (; stack_operator.Count > 0 && stack_number.Count >= 2 && stack_operator.Peek() != "("; stack_operator.Pop()) { int temp3 = Convert.ToInt32(stack_number.Peek()); stack_number.Pop(); int temp4 = Convert.ToInt32(stack_number.Peek()); stack_number.Pop(); stack_number.Push(operator_dected(stack_operator.Peek(), temp3.ToString(), temp4.ToString()).ToString()); } return Convert.ToDouble(stack_number.Peek()); } else { break; } } } catch { } return 0; } #endregion
GITHUB
我是用的是带图形操作界面的githubDesktop,下图为从作业地址克隆后的我的github仓库的结果
该图为更改后,向仓库上传最新版本
下图为向原作者提供修改过的版本
项目测试:
1.运行结果:
2.单元测试:
性能测试:
在性能测试结果里,我发现程序大部分时间花费在了多余的函数调用上,如
for (int i = 0; i < num; i++) { n = random.Next(2, 4); do { str = FormulaCreation(n); formula = str + "!"; ans = operate(formula); if (ans % 1 == 0 && ans > 0 && flag == true) { answers.Add(ans); break; } } while (true); formula = str + "=" + operate(formula); ; formulas.Add(formula); }
此时为更改前,将
formula = str + "=" + operate(formula);
更改为
formula = str + "=" + ans;
即可减少n次operate函数的调用。
总结:
本次作业复习巩固了代码测试与性能优化的相关知识。