144. Binary Tree Preorder Traversal

Solution 1://非递归

public List<Integer> preorderTraversal(TreeNode root) {
List<Integer> result = new ArrayList<>();
if (root == null) {
return result;
}
Stack<TreeNode> stack = new Stack<>();
stack.push(root);
while (!stack.empty()) {
TreeNode node = stack.pop();
result.add(node.val);
if (node.right != null) {
stack.push(node.right);
}
if (node.left != null) {
stack.push(node.left);
}
}
return result;
}

Solution 2://递归

public class Solution {
List<Integer> result = new ArrayList<>();
public List<Integer> preorderTraversal(TreeNode root) {
if (root != null)
helper(root);
return result;
}
private void helper(TreeNode root) {
result.add(root.val);
if (root.left != null)
helper(root.left);
if (root.right != null)
helper(root.right);
}
}
posted @ 2024-01-04 17:45  MarkLeeBYR  阅读(2)  评论(0编辑  收藏  举报