Shell脚本案例

检查脚本

 

修复脚本

#!/bin/bash
#Num_passmin=`cat /etc/login.defs | grep -n ^PASS_MIN_DAYS | awk -F[:] '{print $1}'`
Num_passmin=`sed -n /^"PASS_MIN_DAYS"/= /etc/login.defs`
if [ -n "$Num_passmin" ];then
	Count_passmin=1
	for a in $Num_passmin
	do
	if [ $Count_passmin == 1 ];then
		sed -i $a'c PASS_MIN_DAYS	2' /etc/login.defs
	else
		sed -i $a'c \#PASS_MIN_DAYS 重复配置已替换' /etc/login.defs
	fi
	Count_passmin=$Count_passmin+1
	done
else
	echo "PASS_MIN_DAYS   2" >> /etc/login.defs
fi