摘要: let num = 12345678.002345 let start = (num + '').split('.')[0].split('').reverse() let end = (num + '').split('.')[1] let s = '',cur = '',n = start.le 阅读全文
posted @ 2021-05-27 00:30 国服第一李师师 阅读(313) 评论(0) 推荐(0) 编辑