C# 各种地图坐标系的转换
1 public class ConvertGPS 2 { 3 private static double pi = 3.1415926535897932384626; 4 private static double a = 6378245.0; 5 private static double ee = 0.00669342162296594323; 6 private static double bd_pi = 3.14159265358979324 * 3000.0 / 180.0; 7 8 static Boolean outOfChina(double lat, double lon) 9 { 10 if (lon < 72.004 || lon > 137.8347) 11 return true; 12 if (lat < 0.8293 || lat > 55.8271) 13 return true; 14 return false; 15 } 16 17 static double transformLat(double x, double y) 18 { 19 double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y 20 + 0.2 * Math.Sqrt(Math.Abs(x)); 21 ret += (20.0 * Math.Sin(6.0 * x * pi) + 20.0 * Math.Sin(2.0 * x * pi)) * 2.0 / 3.0; 22 ret += (20.0 * Math.Sin(y * pi) + 40.0 * Math.Sin(y / 3.0 * pi)) * 2.0 / 3.0; 23 ret += (160.0 * Math.Sin(y / 12.0 * pi) + 320 * Math.Sin(y * pi / 30.0)) * 2.0 / 3.0; 24 return ret; 25 } 26 27 static double transformLon(double x, double y) 28 { 29 double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 30 * Math.Sqrt(Math.Abs(x)); 31 ret += (20.0 * Math.Sin(6.0 * x * pi) + 20.0 * Math.Sin(2.0 * x * pi)) * 2.0 / 3.0; 32 ret += (20.0 * Math.Sin(x * pi) + 40.0 * Math.Sin(x / 3.0 * pi)) * 2.0 / 3.0; 33 ret += (150.0 * Math.Sin(x / 12.0 * pi) + 300.0 * Math.Sin(x / 30.0 34 * pi)) * 2.0 / 3.0; 35 return ret; 36 } 37 38 /** 39 * 84 to 火星坐标系 (GCJ-02) World Geodetic System ==> Mars Geodetic System 40 * 41 * @param lat 42 * @param lon 43 * @return 44 */ 45 46 public static PointLatLng gps84_To_Gcj02(PointLatLng Gpoint) 47 { 48 if (outOfChina(Gpoint.Lat, Gpoint.Lng)) 49 { 50 return new PointLatLng(0, 0); 51 } 52 double dLat = transformLat(Gpoint.Lng - 105.0, Gpoint.Lat - 35.0); 53 double dLon = transformLon(Gpoint.Lng - 105.0, Gpoint.Lat - 35.0); 54 double radLat = Gpoint.Lat / 180.0 * pi; 55 double magic = Math.Sin(radLat); 56 magic = 1 - ee * magic * magic; 57 double sqrtMagic = Math.Sqrt(magic); 58 dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi); 59 dLon = (dLon * 180.0) / (a / sqrtMagic * Math.Cos(radLat) * pi); 60 double mgLat = Gpoint.Lat + dLat; 61 double mgLon = Gpoint.Lng + dLon; 62 return new PointLatLng(mgLat, mgLon); 63 } 64 static PointLatLng transform(PointLatLng Gpoint) 65 { 66 if (outOfChina(Gpoint.Lat, Gpoint.Lng)) 67 { 68 return new PointLatLng(Gpoint.Lat, Gpoint.Lng); 69 } 70 double dLat = transformLat(Gpoint.Lng - 105.0, Gpoint.Lat - 35.0); 71 double dLon = transformLon(Gpoint.Lng - 105.0, Gpoint.Lat - 35.0); 72 double radLat = Gpoint.Lat / 180.0 * pi; 73 double magic = Math.Sin(radLat); 74 magic = 1 - ee * magic * magic; 75 double sqrtMagic = Math.Sqrt(magic); 76 dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi); 77 dLon = (dLon * 180.0) / (a / sqrtMagic * Math.Cos(radLat) * pi); 78 double mgLat = Gpoint.Lat + dLat; 79 double mgLon = Gpoint.Lng + dLon; 80 return new PointLatLng(mgLat, mgLon); 81 } 82 83 /** 84 * * 火星坐标系 (GCJ-02) to 84 * * @param lon * @param lat * @return 85 * */ 86 public static PointLatLng gcj02_To_Gps84(PointLatLng Gpoint) 87 { 88 PointLatLng gps = transform(Gpoint); 89 double lontitude = Gpoint.Lng * 2 - gps.Lng; 90 double latitude = Gpoint.Lat * 2 - gps.Lat; 91 return new PointLatLng(latitude, lontitude); 92 } 93 /** 94 * 火星坐标系 (GCJ-02) 与百度坐标系 (BD-09) 的转换算法 将 GCJ-02 坐标转换成 BD-09 坐标 95 * 96 * @param gg_lat 97 * @param gg_lon 98 */ 99 public static PointLatLng gcj02_To_Bd09(PointLatLng Gpoint) 100 { 101 double x = Gpoint.Lng, y = Gpoint.Lat; 102 double z = Math.Sqrt(x * x + y * y) + 0.00002 * Math.Sin(y * bd_pi); 103 double theta = Math.Atan2(y, x) + 0.000003 * Math.Cos(x * bd_pi); 104 double bd_lon = z * Math.Cos(theta) + 0.0065; 105 double bd_lat = z * Math.Sin(theta) + 0.006; 106 return new PointLatLng(bd_lat, bd_lon); 107 } 108 109 /** 110 * * 火星坐标系 (GCJ-02) 与百度坐标系 (BD-09) 的转换算法 * * 将 BD-09 坐标转换成GCJ-02 坐标 * * @param 111 * bd_lat * @param bd_lon * @return 112 */ 113 public static PointLatLng bd09_To_Gcj02(PointLatLng bdPoint) 114 { 115 double x = bdPoint.Lng - 0.0065, y = bdPoint.Lat - 0.006; 116 double z = Math.Sqrt(x * x + y * y) - 0.00002 * Math.Sin(y * bd_pi); 117 double theta = Math.Atan2(y, x) - 0.000003 * Math.Cos(x * bd_pi); 118 double gg_lon = z * Math.Cos(theta); 119 double gg_lat = z * Math.Sin(theta); 120 return new PointLatLng(gg_lat, gg_lon); 121 } 122 123 /** 124 * (BD-09)-->84 125 * @param bd_lat 126 * @param bd_lon 127 * @return 128 */ 129 public static PointLatLng bd09_To_Gps84(PointLatLng bdPoint) 130 { 131 132 PointLatLng gcj02 = bd09_To_Gcj02(bdPoint); 133 PointLatLng map84 = gcj02_To_Gps84(gcj02); 134 return map84; 135 136 } 137 /** 138 * 84-->(BD-09) 139 * @param bd_lat 140 * @param bd_lon 141 * @return 142 */ 143 public static PointLatLng Gps84_To_bd09(PointLatLng gpsPoint) 144 { 145 PointLatLng gcj02 = gps84_To_Gcj02(gpsPoint); 146 PointLatLng bd09 = gcj02_To_Bd09(gcj02); 147 return bd09; 148 149 } 150 151 } 152 153 public class PointLatLng 154 { 155 156 public PointLatLng(double lat, double lng) 157 { 158 Lat = lat; 159 Lng = lng; 160 } 161 public double Lat { get; set; } 162 public double Lng { get; set; } 163 }