C# 各种地图坐标系的转换

  1 public class ConvertGPS
  2     {
  3         private static double pi = 3.1415926535897932384626;
  4         private static double a = 6378245.0;
  5         private static double ee = 0.00669342162296594323;
  6         private static double bd_pi = 3.14159265358979324 * 3000.0 / 180.0;
  7 
  8         static Boolean outOfChina(double lat, double lon)
  9         {
 10             if (lon < 72.004 || lon > 137.8347)
 11                 return true;
 12             if (lat < 0.8293 || lat > 55.8271)
 13                 return true;
 14             return false;
 15         }
 16 
 17         static double transformLat(double x, double y)
 18         {
 19             double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y
 20                     + 0.2 * Math.Sqrt(Math.Abs(x));
 21             ret += (20.0 * Math.Sin(6.0 * x * pi) + 20.0 * Math.Sin(2.0 * x * pi)) * 2.0 / 3.0;
 22             ret += (20.0 * Math.Sin(y * pi) + 40.0 * Math.Sin(y / 3.0 * pi)) * 2.0 / 3.0;
 23             ret += (160.0 * Math.Sin(y / 12.0 * pi) + 320 * Math.Sin(y * pi / 30.0)) * 2.0 / 3.0;
 24             return ret;
 25         }
 26 
 27         static double transformLon(double x, double y)
 28         {
 29             double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1
 30                     * Math.Sqrt(Math.Abs(x));
 31             ret += (20.0 * Math.Sin(6.0 * x * pi) + 20.0 * Math.Sin(2.0 * x * pi)) * 2.0 / 3.0;
 32             ret += (20.0 * Math.Sin(x * pi) + 40.0 * Math.Sin(x / 3.0 * pi)) * 2.0 / 3.0;
 33             ret += (150.0 * Math.Sin(x / 12.0 * pi) + 300.0 * Math.Sin(x / 30.0
 34                     * pi)) * 2.0 / 3.0;
 35             return ret;
 36         }
 37 
 38         /** 
 39         * 84 to 火星坐标系 (GCJ-02) World Geodetic System ==> Mars Geodetic System 
 40         *  
 41         * @param lat 
 42         * @param lon 
 43         * @return 
 44         */
 45 
 46         public static PointLatLng gps84_To_Gcj02(PointLatLng Gpoint)
 47         {
 48             if (outOfChina(Gpoint.Lat, Gpoint.Lng))
 49             {
 50                 return new PointLatLng(0, 0);
 51             }
 52             double dLat = transformLat(Gpoint.Lng - 105.0, Gpoint.Lat - 35.0);
 53             double dLon = transformLon(Gpoint.Lng - 105.0, Gpoint.Lat - 35.0);
 54             double radLat = Gpoint.Lat / 180.0 * pi;
 55             double magic = Math.Sin(radLat);
 56             magic = 1 - ee * magic * magic;
 57             double sqrtMagic = Math.Sqrt(magic);
 58             dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);
 59             dLon = (dLon * 180.0) / (a / sqrtMagic * Math.Cos(radLat) * pi);
 60             double mgLat = Gpoint.Lat + dLat;
 61             double mgLon = Gpoint.Lng + dLon;
 62             return new PointLatLng(mgLat, mgLon);
 63         }
 64         static PointLatLng transform(PointLatLng Gpoint)
 65         {
 66             if (outOfChina(Gpoint.Lat, Gpoint.Lng))
 67             {
 68                 return new PointLatLng(Gpoint.Lat, Gpoint.Lng);
 69             }
 70             double dLat = transformLat(Gpoint.Lng - 105.0, Gpoint.Lat - 35.0);
 71             double dLon = transformLon(Gpoint.Lng - 105.0, Gpoint.Lat - 35.0);
 72             double radLat = Gpoint.Lat / 180.0 * pi;
 73             double magic = Math.Sin(radLat);
 74             magic = 1 - ee * magic * magic;
 75             double sqrtMagic = Math.Sqrt(magic);
 76             dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);
 77             dLon = (dLon * 180.0) / (a / sqrtMagic * Math.Cos(radLat) * pi);
 78             double mgLat = Gpoint.Lat + dLat;
 79             double mgLon = Gpoint.Lng + dLon;
 80             return new PointLatLng(mgLat, mgLon);
 81         }
 82 
 83         /** 
 84          * * 火星坐标系 (GCJ-02) to 84 * * @param lon * @param lat * @return 
 85          * */
 86         public static PointLatLng gcj02_To_Gps84(PointLatLng Gpoint)
 87         {
 88             PointLatLng gps = transform(Gpoint);
 89             double lontitude = Gpoint.Lng * 2 - gps.Lng;
 90             double latitude = Gpoint.Lat * 2 - gps.Lat;
 91             return new PointLatLng(latitude, lontitude);
 92         }
 93         /** 
 94          * 火星坐标系 (GCJ-02) 与百度坐标系 (BD-09) 的转换算法 将 GCJ-02 坐标转换成 BD-09 坐标 
 95          *  
 96          * @param gg_lat 
 97          * @param gg_lon 
 98          */
 99         public static PointLatLng gcj02_To_Bd09(PointLatLng Gpoint)
100         {
101             double x = Gpoint.Lng, y = Gpoint.Lat;
102             double z = Math.Sqrt(x * x + y * y) + 0.00002 * Math.Sin(y * bd_pi);
103             double theta = Math.Atan2(y, x) + 0.000003 * Math.Cos(x * bd_pi);
104             double bd_lon = z * Math.Cos(theta) + 0.0065;
105             double bd_lat = z * Math.Sin(theta) + 0.006;
106             return new PointLatLng(bd_lat, bd_lon);
107         }
108 
109         /** 
110         * * 火星坐标系 (GCJ-02) 与百度坐标系 (BD-09) 的转换算法 * * 将 BD-09 坐标转换成GCJ-02 坐标 * * @param 
111         * bd_lat * @param bd_lon * @return 
112         */
113         public static PointLatLng bd09_To_Gcj02(PointLatLng bdPoint)
114         {
115             double x = bdPoint.Lng - 0.0065, y = bdPoint.Lat - 0.006;
116             double z = Math.Sqrt(x * x + y * y) - 0.00002 * Math.Sin(y * bd_pi);
117             double theta = Math.Atan2(y, x) - 0.000003 * Math.Cos(x * bd_pi);
118             double gg_lon = z * Math.Cos(theta);
119             double gg_lat = z * Math.Sin(theta);
120             return new PointLatLng(gg_lat, gg_lon);
121         }
122 
123         /** 
124          * (BD-09)-->84 
125          * @param bd_lat 
126          * @param bd_lon 
127          * @return 
128          */
129         public static PointLatLng bd09_To_Gps84(PointLatLng bdPoint)
130         {
131 
132             PointLatLng gcj02 = bd09_To_Gcj02(bdPoint);
133             PointLatLng map84 = gcj02_To_Gps84(gcj02);
134             return map84;
135 
136         }
137         /** 
138          * 84-->(BD-09)
139          * @param bd_lat 
140          * @param bd_lon 
141          * @return 
142          */
143         public static PointLatLng Gps84_To_bd09(PointLatLng gpsPoint)
144         {
145             PointLatLng gcj02 = gps84_To_Gcj02(gpsPoint);
146             PointLatLng bd09 = gcj02_To_Bd09(gcj02);
147             return bd09;
148 
149         }
150 
151     }
152 
153   public class PointLatLng
154     {
155 
156         public PointLatLng(double lat, double lng)
157         {
158             Lat = lat;
159             Lng = lng;
160         }
161         public double Lat { get; set; }
162         public double Lng { get; set; }
163     }

 

posted @ 2021-10-26 15:15  Lxk-  阅读(647)  评论(0编辑  收藏  举报