摘要: test 1 #include <stdio.h> #define N 4 #define M 2 void test1() { int x[N] = {1, 9, 8, 4}; int i; printf("sizeof(x) = %d\n", sizeof(x)); for (i = 0; i 阅读全文
posted @ 2024-11-10 01:01 璐Luzi 阅读(7) 评论(0) 推荐(0) 编辑