实验6

task 4

#include <stdio.h>
#define N 10

typedef struct {
    char isbn[20];          
    char name[80];          
    char author[80];        
    double sales_price;     
    int  sales_count;       
} Book;

void output(Book x[], int n);
void sort(Book x[], int n);
double sales_amount(Book x[], int n);

int main() {
    Book x[N] = { {"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
                 {"978-7-308-17047-5", "自由与爱之地:入以色列记", "云也退", 49 , 30},
                 {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
                 {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90},
                 {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
                 {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
                 {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
                 {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
                 {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
                 {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59} };

    printf("图书销量排名(按销售册数): \n");
    sort(x, N);
    output(x, N);

    printf("\n图书销售总额: %.2f\n", sales_amount(x, N));

    return 0;
}

void output(Book x[], int n) {
    int i;

    printf("ISBN号\t\t      书名\t\t\t      作者\t\t    售价\n");

    for (i = 0;i < n;i++)
        printf("%-20s  %-30s  %-20s  %.1f\n", x[i].isbn, x[i].name, x[i].author, x[i].sales_price);
}

void sort(Book x[], int n) {
    int i, j;
    Book t;

    for (i = 0;i < n - 1;i++) {
        for (j = 0;j < n - 1 - i;j++) {
            if (x[j].sales_count < x[j + 1].sales_count) {
                t = x[j];
                x[j] = x[j + 1];
                x[j + 1] = t;
            }
        }
    }
}

double sales_amount(Book x[], int n) {
    double total = 0.0;
    int i;

    for (i = 0;i < n;i++) 
        total += x[i].sales_price * x[i].sales_count;

    return total;
}

 

task 5

#include <stdio.h>

typedef struct {
    int year;
    int month;
    int day;
} Date;

void input(Date* pd);                  
int day_of_year(Date d);                
int compare_dates(Date d1, Date d2);   

void test1() {
    Date d;
    int i;

    printf("输入日期:(以形如2024-12-16这样的形式输入)\n");
    for (i = 0; i < 3; ++i) {
        input(&d);
        printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d));
    }
}

void test2() {
    Date Alice_birth, Bob_birth;
    int i;
    int ans;

    printf("输入Alice和Bob出生日期:(以形如2024-12-16这样的形式输入)\n");
    for (i = 0; i < 3; ++i) {
        input(&Alice_birth);
        input(&Bob_birth);
        ans = compare_dates(Alice_birth, Bob_birth);

        if (ans == 0)
            printf("Alice和Bob一样大\n\n");
        else if (ans == -1)
            printf("Alice比Bob大\n\n");
        else
            printf("Alice比Bob小\n\n");
    }
}

int main() {
    printf("测试1: 输入日期, 打印输出这是一年中第多少天\n");
    test1();

    printf("\n测试2: 两个人年龄大小关系\n");
    test2();
}

void input(Date* pd) {
    scanf("%d-%02d-%02d", &(pd->year), &(pd->month), &(pd->day));
}

int day_of_year(Date d) {
    int i, total = 0;

    if ((d.year % 4 == 0 && d.year % 100 != 0) || d.year % 400 == 0) {
        for (i = 0;i < d.month;i++) {
            if (i == 2 || i == 4 || i == 6 || i == 7 || i == 9 || i == 11)
                total += 31;
            else if (i == 1)
                total += 29;
            else if (i == 3 || i == 5 || i == 8 || i == 10)
                total += 30;
        }
        total += d.day;
    }
    else {
        for (i = 0;i < d.month;i++) {
            if (i == 2 || i == 4 || i == 6 || i == 7 || i == 9 || i == 11)
                total += 31;
            else if (i == 1)
                total += 28;
            else if (i == 3 || i == 5 || i == 8 || i == 10)
                total += 30;
        }
        total += d.day;
    }
    return total;
}

int compare_dates(Date d1, Date d2) {
    int ans;

    if (d1.year < d2.year)
        ans = -1;
    else if (d1.year > d2.year)
        ans = 1;
    else {
        if (d1.month < d2.month)
            ans = -1;
        else if (d1.month > d2.month)
            ans = 1;
        else {
            if (d1.day < d2.day)
                ans = -1;
            else if (d1.day > d2.day)
                ans = 1;
            else
                ans = 0;
        }
    }
    return ans;
}

 

task 6

#include <stdio.h>
#include <string.h>

enum Role{admin,student,teacher};

typedef struct {
    char username[20];
    char password[20];
    enum Role type;
}Account;

void output(Account x[], int n);

int main() {
    Account x[] = { {"A1001", "123456", student},
                    {"A1002", "123abcdef", student},
                    {"A1009", "xyz12121", student},
                    {"X1009", "9213071x", admin},
                    {"C11553", "129dfg32k", teacher},
                    {"X3005", "921kfmg917", student} };
    int n;
    n = sizeof(x) / sizeof(Account);
    output(x, n);

    return 0;
}

void output(Account x[], int n) {
    int i,j;

    for (i = 0;i < n;i++) {
        printf("%-10s", x[i].username);

        for (j = 0;j < strlen(x[i].password);j++)
            printf("*");
        printf("\t");

        switch (x[i].type) {
        case student:printf("student\n");break;
        case admin:printf("admin\n");break;
        case teacher:printf("teacher\n");break;
        }
    }
}

 

task 7

#include <stdio.h>
#include <string.h>
#define N 10

typedef struct {
    char name[20];
    char phone[20];
    int vip;
}Contact;

void set_vip_contact(Contact x[], int n, char name[]);
void output(Contact x[], int n);
void display(Contact x[], int n);
void sort(Contact x[], int n, int vip_cnt);

int main() {
    Contact list[N] = { {"刘一", "15510846604", 0},
                       {"陈二", "18038747351", 0},
                       {"张三", "18853253914", 0},
                       {"李四", "13230584477", 0},
                       {"王五", "15547571923", 0},
                       {"赵六", "18856659351", 0},
                       {"周七", "17705843215", 0},
                       {"孙八", "15552933732", 0},
                       {"吴九", "18077702405", 0},
                       {"郑十", "18820725036", 0} };
    int vip_cnt, i;
    char name[20];

    printf("显示原始通讯录信息:\n");
    output(list, N);

    printf("\n输入要设置的紧急联系人个数:");
    scanf("%d", &vip_cnt);
    printf("输入%d个紧急联系人姓名:\n", vip_cnt);

    for (i = 0;i < vip_cnt;i++) {
        scanf("%s", name);
        set_vip_contact(list, N, name);
    }

    printf("\n显示通讯录列表:(按姓名字典升序排列,紧急联系人最先显示)\n");
    sort(list, N, vip_cnt);
    display(list, N);

    return 0;
}

void set_vip_contact(Contact x[], int n, char name[]) {
    int i;

    for (i = 0;i < n;i++) {
        if (strcmp(name, x[i].name) == 0)
            x[i].vip = 1;
    }
}

void display(Contact x[], int n) {
    output(x, n);
}

void output(Contact x[], int n) {
    int i;

    for (i = 0;i < n;++i) {
        printf("%-10s%-15s", x[i].name, x[i].phone);
        if (x[i].vip)
            printf("%5s", "*");
        printf("\n");
    }
}

void sort(Contact x[], int n, int vip_cnt) {
    int i, j;
    Contact t;

    for (i = 0;i < n;i++) {
        if (x[i].vip) {
            for (j = 0;j < vip_cnt;j++) {
                t = x[j];
                x[j] = x[i];
                x[i] = t;
            }
        }
    }

    for (i = 0;i < vip_cnt-1;i++) {
        for (j = 0;j < vip_cnt - 1 - i;j++) {
            if (strcmp(x[j].name, x[j + 1].name) > 0) {
                t = x[j];
                x[j] = x[j + 1];
                x[j + 1] = t;
            }
        }
    }

    for (i = 0;i < n - 3;i++) {
        for (j = vip_cnt;j < n - 1 - i;j++) {
            if (strcmp(x[j].name, x[j + 1].name) > 0) {
                t = x[j];
                x[j] = x[j + 1];
                x[j + 1] = t;
            }
        }
    }
}

 

posted @ 2024-12-21 13:46  璐Luzi  阅读(1)  评论(0编辑  收藏  举报