用python实现四则运算的生成与判定

小组成员：2252316，2252326

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import random

def generate_question():
    operators= ['+', '-', '*', '/']
    while 1:
        operator1 = random.choice(operators)
        operator2 = random.choice(operators)

        num1 = random.randint(1, 100)
        num2 = random.randint(1, 100)
        num3 = random.randint(1, 100)

        if operator2 == '/':
            num2 = num3 * random.randint(1, 10)
        if operator1 == '/':
            num1 = num2 * random.randint(1, 10)
        question = str(num1) + ' ' + operator1 + ' ' + str(num2) + ' ' + operator2 + ' ' + str(num3)
        answer = int(eval(question))
        if answer>0 and answer<100:
            break

    return question, answer


def generate_questions(num_questions):
    questions = []
    answers = []

    for _ in range(num_questions):
        question, answer = generate_question()
        questions.append(question)
        answers.append(answer)

    return questions, answers


def check_answer(question, user_answer):
    correct_answer = int(eval(question))
    return user_answer == correct_answer

num_questions = int(input("题目数量："))
questions, answers = generate_questions(num_questions)

score = 0
for i in range(num_questions):
    print(f"Question {i + 1}: {questions[i]} = ?")
    user_answer = int(input("Your answer: "))

    if check_answer(questions[i], user_answer):
        print("Correct!\n")
        score += 1
    else:
        print(f"Wrong! The correct answer is: {answers[i]}\n")

print(f"Your final score is: {score}/{num_questions}")

通过随机函数生成随机运算符以及随机的数字，其中对于除法的处理花了一些功夫，因为想要结果为整数，所以我采用倒推的方法，比如a/b/c，那么就先随机生成c，然后用c一个随机数得到b，再一个随机数得到a，这样的办法来实现，另外一点是由于python3中固定完成除法会保留浮点型，所以采用强制转换成整型的方式来判断，这次尝试中我出现了很多记忆不准确的地方，小组合作商讨互相纠错才得以最终实现。