摘要: 获取一段时间内所有的小时SELECT to_date('2013-07-01 12', 'yyyy-mm-dd hh24') + (ROWNUM - 1) / 24 sdate FROM dualCONNECT BY ROWNUM <= (to_date('2013-07-02 22', 'yyyy... 阅读全文
posted @ 2015-01-30 16:58 Look_Sun 阅读(254) 评论(0) 推荐(0) 编辑