二叉树遍历

https://www.cnblogs.com/zhi-leaf/p/10813048.html

 

 

前序遍历

访问顺序：先根节点，再左子树，最后右子树；上图的访问结果为：GDAFEMHZ。

 

中序遍历

访问顺序：先左子树，再根节点，最后右子树；上图的访问结果为：ADEFGHMZ。

 

后续遍历

访问顺序：先左子树，再右子树，最后根节点，上图的访问结果为：AEFDHZMG。

1）递归实现

 

package com.logan.Algo;

import java.util.LinkedList;
import java.util.Queue;
import java.util.Stack;

public class Traverse {
    //前序遍历，结果：GDAFEMHZ
    public void preOrderTraverse1(TreeNode root) {
        if(root != null) {
            System.out.println(root.val + "->");
            preOrderTraverse1(root.left);
            preOrderTraverse1(root.right);
        }
    }
    
    public void preOrderTraverse2(TreeNode root) {
        Stack<TreeNode> stack = new Stack();
        TreeNode node = root;
        while(node != null || !stack.empty()) {
            if(node != null) {
                System.out.println(node.val + "->");
                stack.push(node);
                node = node.left;
            }else {
                TreeNode tem = stack.pop();
                node = tem.right;
            }
        }
    }
    //中序遍历，结果：ADEFGHMZ
    public void inOrderTraverse1(TreeNode root) {
        if(root != null) {
            inOrderTraverse1(root.left);
            System.out.println(root.val + "->");
            inOrderTraverse1(root.right);
        }
    }
    
    public void inOrderTraverse2(TreeNode root) {
        Stack<TreeNode> stack = new Stack<>();
        TreeNode node = root;
        while(node != null || !stack.isEmpty()) {
            if(node != null) {
                stack.push(node);
                node = node.left;
            }else {
                TreeNode tem = stack.pop();
                System.out.println(tem.val + "->");
                node = tem.right;
            }
        }
    }
    
    //后续遍历，结果：AEFDHZMG
    public void postOrderTraverse1(TreeNode root) {
        if(root != null) {
            postOrderTraverse1(root.left);
            postOrderTraverse1(root.right);
            System.out.println(root.val + "->");
        }
    }
    
    public void postOrderTraverse2(TreeNode root) {
        TreeNode cur, pre = null;
        Stack<TreeNode> stack = new Stack<>();
        stack.push(root);
        while(!stack.isEmpty()) {
            cur = stack.peek();
            if((cur.left == null && cur.right == null) || (pre != null && (pre==cur.left || pre ==cur.right))) {
                System.out.println(cur.val + "->");
                stack.pop();
                pre=cur;
            }else {
                if(cur.right != null)
                    stack.push(cur.right);
                if(cur.left != null)
                    stack.push(cur.left);
            }
        }
    }
    //层次遍历，结果：GDMAFHZE
    public void levelOrderTraverse(TreeNode root) {
        if(root == null) {
            return;
        }
        Queue<TreeNode> queue = new LinkedList<TreeNode>();
        queue.add(root);
        
        while(!queue.isEmpty()) {
            TreeNode node = queue.poll();
            System.out.println(node.val + "->");
            if(node.left != null) {
                queue.add(node.left);
            }
            if(node.right != null) {
                queue.add(node.right);
            }
        }
    }
}