刷题05

组合

class Solution {
    List<List<Integer>> sum=new LinkedList<>();
    LinkedList<Integer> path=new LinkedList<>();
    public List<List<Integer>> combine(int n, int k) {
        get(n,k,1);
        return sum;
    }
    public void get(int n,int k,int startIndex)
    {
        if(path.size()==k)
        {
            sum.add(new LinkedList<>(path));
            return;
        }
        for(int i=startIndex;i<=n;i++)
        {
            path.add(i);
            get(n,k,i+1);
            path.removeLast();
        }
    }
}

组合总合Ⅲ

class Solution {
    List<List<Integer>> sum=new LinkedList<>();
    LinkedList<Integer> path=new LinkedList<>();
	public List<List<Integer>> combinationSum3(int k, int n) {
		get(n,k,1);
        return sum;
	}
    public void get(int n,int k,int startIndex)
    {
        if(path.size()==k&&n==0)
        {
            sum.add(new LinkedList<>(path));
            return;
        }
        for(int i=startIndex;i<=9;i++)
        {
            path.add(i);
            get(n-i,k,i+1);
            path.removeLast();
        }
    }
}

电话号码组合

class Solution {
    List<String> sum=new LinkedList<>();
    StringBuilder sb=new StringBuilder();
    public List<String> letterCombinations(String digits) {
       if(digits.equals("")) return sum;
       String[] nums={"","","abc","def","ghi","jkl","mno","pqrs","tuv","wxyz"};
       backtracking(digits,nums,0);
       return sum;
    }
    public void backtracking(String digits,String[] nums,int startIndex)
    {
        if(sb.length()==digits.length())
        {
            sum.add(sb.toString());
            return;
        }
        String str=nums[digits.charAt(startIndex)-'0'];
        for(int i=0;i<str.length();i++)
        {
            sb.append(str.charAt(i));
            backtracking(digits,nums,startIndex+1);
            sb.deleteCharAt(sb.length()-1);
        }
    } 
  
}

组合总合

class Solution {
    List<List<Integer>> sum=new LinkedList<>();
    LinkedList<Integer> path=new LinkedList<>();
    public List<List<Integer>> combinationSum(int[] candidates, int target) {
       Arrays.sort(candidates);
       backtracking(candidates,target,0,0);
       return sum;
    }
    public void backtracking(int[] candidates,int target,int startIndex,int count)
    {
        if(count==target)
        {
            sum.add(new LinkedList<>(path));
            return;
        }
        for(int i=startIndex;i<candidates.length;i++)
        {
            if(count+candidates[i]>target)  break;
            path.add(candidates[i]);
            count=count+candidates[i];
            backtracking(candidates,target,i,count);
            path.removeLast();
            count=count-candidates[i];
        }
    }

}

组合总合Ⅱ

class Solution {
    List<List<Integer>> sum=new LinkedList<>();
    LinkedList<Integer> path=new LinkedList<>();
    //Set<List<Integer>> set=new HashSet<>();
    public List<List<Integer>> combinationSum2(int[] candidates, int target) {
        Arrays.sort(candidates);
        boolean[] used=new boolean[candidates.length];
        backtracking(candidates,target,0,0,used);
        return sum;
    }
   public void backtracking(int[] candidates,int target,int startIndex,int count,boolean[] used)
   {
       if(count==target)
       {
           sum.add(new LinkedList<>(path));
          // set.add(new LinkedList<>(path));
           return;
       }
       for(int i=startIndex;i<candidates.length;i++)
       {
           if(i>0&&candidates[i]==candidates[i-1]&&used[i-1]==false)
           {
               continue;
              // break;
           }
           if(count>target) return;
           path.add(candidates[i]);
           used[i]=true;
           count+=candidates[i];
           backtracking(candidates,target,i+1,count,used);
           path.removeLast();
           used[i]=false;
           count-=candidates[i];
       }
   }
}
posted @ 2022-02-05 11:54  一刹流云散  阅读(17)  评论(0编辑  收藏  举报