python获取文件路径

?

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25

摘自：https://blog.csdn.net/Poo_Chai/article/details/89764001<br><br>import os root_path = os.path.abspath(os.path.join(os.getcwd(), ".."))    print("""***********************  Path test:start..... ********************""") print("***获得当前路径***") cwd = os.getcwd() print('current path:', cwd) print('File exist or not:', os.path.exists('C:\\Users\\leo\\Desktop\\neu.softwarecollege.mySocialCloudSimulator/' \                                            '//data/relationship-pairs.csv')) print('File exist or not:', os.path.exists('../data/relationship-pairs.csv')) print("""***********************  Path test:end..... ********************""") print(os.path.abspath(os.path.dirname(__file__)))    print('***获取上级目录***') print(os.path.abspath(os.path.dirname(os.path.dirname(__file__)))) print(os.path.abspath(os.path.dirname(os.getcwd()))) path = os.path.abspath(os.path.join(os.getcwd(), "..")) print('path=', path) print('File exist or not:', os.path.exists(path+'/data/relationship-pairs.csv'))    print('***获取上上级目录***') print(os.path.abspath(os.path.join(os.getcwd(), "../.."))) ———————————————— 版权声明：本文为CSDN博主「Poo_Chai」的原创文章，遵循 CC 4.0 BY-SA 版权协议，转载请附上原文出处链接及本声明。 原文链接：https://blog.csdn.net/Poo_Chai/article/details/89764001

　　python获取文件路径的代码如上所示。运行结果如下：