摘要:
https://www.cnblogs.com/grandyang/p/4271456.html leetcode 132 https://www.cnblogs.com/grandyang/p/7404777.html leetcode 647 将字符串切割为回文的最小切割数:动态规划 p[i][ 阅读全文
摘要:
https://www.cnblogs.com/grandyang/p/4294105.html 不同的子序列: 动态规划,dp[i][j]代表s[0...i]中t[0...j]有的个数。写出矩阵,找规律。 class Solution { public: int numDistinct(strin 阅读全文