[LeetCode][JavaScript]Missing Number

Missing Number

Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array.

For example,
Given nums = [0, 1, 3] return 2.

Note:
Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?

https://leetcode.com/problems/missing-number/

 

 


 

 

求出序列中缺少的那个数,序列肯定是乱序的。

把0到n的数相加(等差数列求和),再一个个减掉,最后剩下的就是结果。

本来以为相加可能超过了长度限制,要用大数加减法,试了一下并不用。

 1 /**
 2  * @param {number[]} nums
 3  * @return {number}
 4  */
 5 var missingNumber = function(nums) {
 6     var i, res = 0;
 7     res = parseInt((nums.length + 1) * nums.length / 2);
 8     for(i = 0; i < nums.length; i++){
 9         res -= nums[i];
10     }
11     return res;
12 };

 

 

 

posted @ 2015-08-24 10:27  `Liok  阅读(383)  评论(0编辑  收藏  举报