1 #include <stdio.h>
2 #include <math.h>
3
4 int leap_year(int year){
5 if(year%400==0 || (year%4==0 && year%100!=0)){
6 return 1;//是闰年
7 }else{
8 return 0;//不是闰年
9 }
10 }
11
12 int mon_d(int year,int mon){
13 int i, days = 0,mon_days[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
14 //for(i=1;i<mon;i++){
15 if(mon >= 2){
16 if(leap_year(year) == 1){
17 mon_days[1] = 29;
18 for(i=0; i<mon-1; i++){
19 days += mon_days[i];
20 }
21 return days;
22 }else{
23 for(i=0;i < mon-1;i++){
24 days += mon_days[i];
25
26 }
27 return days;
28 }
29 }
30 //}
31 return 0;
32 }
33
34 int main(){
35
36 int y1, m1, d1, y2, m2, d2, i, y, day_to_day = 0;
37 printf("请您输入一个日期（eg：2008-8-8）: ");
38
39 scanf("%d-%d-%d",&y1,&m1,&d1);
40
41 printf("请您再输入一个日期（eg：2008-8-8）: ");
42 scanf("%d-%d-%d",&y2,&m2,&d2);
43 //printf("%d-%d-%d\n",y1,m1,d1);
44 //printf("%d-%d-%d\n",y2,m2,d2);
45
46 y = y2-y1;
47
48 if(y == 0){
49 day_to_day = mon_d(y2,m2) + d2 - (mon_d(y1,m1) + d1);
50 }else if(y == 1){
51 day_to_day = 365 + leap_year(y1) - ( mon_d(y1,m1) + d1 ) + mon_d(y2,m2) +d2;
52 }else{
53 for(i=y1+1; i<y2; i++){
54 day_to_day += 365 + leap_year(i);
55 }
56 day_to_day += 365 + leap_year(y1) - ( mon_d(y1,m1) + d1 ) + mon_d(y2,m2) +d2;;
57 }
58 printf("这两个日期相差的天数是： %d 天\n",day_to_day);
59
60 }
