python opencv3 FLANN单应性匹配

git:https://github.com/linyi0604/Computer-Vision

匹配准确率非常高。

单应性指的是图像在投影发生了 畸变后仍然能够有较高的检测和匹配准确率

 

 1 # coding:utf-8
 2 
 3 """
 4 单应性匹配:
 5     两幅图像中的一幅 出现投影畸变的时候,他们还能彼此匹配
 6 """
 7 
 8 import cv2
 9 import numpy as np
10 # 最小匹配数量设为10个, 大于这个数量从中筛选出10个最好的
11 MIN_MATCH_COUNT = 10
12 
13 # 读入两幅图片 图片中有相同部分
14 img1 = cv2.imread("../data/logo1.png", cv2.IMREAD_GRAYSCALE)
15 img2 = cv2.imread("../data/album1.png", cv2.IMREAD_GRAYSCALE)
16 
17 # 获取sift特征检测器
18 sift = cv2.xfeatures2d.SIFT_create()
19 # 检测关键点 计算描述符
20 kp1, des1 = sift.detectAndCompute(img1, None)
21 kp2, des2 = sift.detectAndCompute(img2, None)
22 
23 # kdtree建立索引方式的常量参数
24 FLANN_INDEX_KDTREE = 0
25 index_params = dict(algorithm=FLANN_INDEX_KDTREE, trees=5)
26 search_params = dict(checks=50) # checks指定索引树要被遍历的次数
27 flann = cv2.FlannBasedMatcher(index_params, search_params)
28 # 进行匹配搜索
29 matches = flann.knnMatch(des1, des2, k=2)
30 
31 # 寻找距离近的放入good列表
32 good = []
33 for m, n in matches:
34     if m.distance < 0.7 * n.distance:
35         good.append(m)
36 
37 # 如果足够多  就筛选
38 if len(good) > MIN_MATCH_COUNT:
39     # 通过距离近的描述符 找到两幅图片的关键点
40     src_pts = np.float32([kp1[m.queryIdx].pt for m in good]).reshape(-1, 1, 2)
41     dst_pts = np.float32([kp2[m.trainIdx].pt for m in good]).reshape(-1, 1, 2)
42 
43     # 单应性匹配图关键点匹配线。。不懂啥意思
44     M, mask = cv2.findHomography(src_pts, dst_pts, cv2.RANSAC, 5.0)
45     matchesMask = mask.ravel().tolist()
46 
47     h, w = img1.shape
48 
49     # 计算第二张图相对于第一张图的畸变
50     pts = np.float32([[0, 0], [0, h-1], [w-1, 0]]).reshape(-1, 1, 2)
51     dst = cv2.perspectiveTransform(pts, M)
52     img2 = cv2.polylines(img2, [np.int32(dst)], True, 255, 3, cv2.LINE_AA)
53 else:
54     matchesMask = None
55 
56 draw_params = dict(
57     matchColor=(0, 255, 0),
58     singlePointColor=None,
59     matchesMask=matchesMask,
60     flags=2
61 )
62 
63 img3 = cv2.drawMatches(img1, kp1, img2, kp2, good, None, **draw_params)
64 cv2.imshow("", img3)
65 cv2.waitKey()

 

posted @ 2018-08-07 11:08  稀里糊涂林老冷  阅读(5255)  评论(0编辑  收藏  举报