JAVA.9

1.有10个评委打分,(去掉一个最高一个最低)求平均分。 
package ssa;

import java.util.Scanner;

public class lianxi {
	public static void main(String[] args) {
		int[] arry = new int[] { 1,2,3,4,5,6,7,8,9,10};
		for (int i = 0; i < arry.length - 1; i++) {
			for (int j = 0; j <arry.length - 1 - i; j++) {
				if (arry[j] > arry[j + 1]) {
					int tmp = arry[j];
					arry[j] = arry[j + 1];
					arry[j + 1] = tmp;
				}
			}
		}
		int sum = 0;
		for (int i = 1; i < arry.length - 1; i++) {
			sum += arry[i];
		}
		System.out.println("平均分为:" + sum / (arry.length - 2.0));
	}

}

  

 2.自学一下Java随机数,生成一个长度为10的随机数组(每个数的范围是0~99),排序后输出。
package ssa;

import java.util.Random;


public class lianxi {
	public static void main(String[] args) {
		int[] arry = new int[10];
        Random r=new Random();
        for (int i = 0; i < arry.length; i++) {
        	arry[i]=r.nextInt(100);
        }
        int t;
        for (int i = 0; i < arry.length - 1; i++) {
            for (int j = 0; j < arry.length-1-i; j++) {
                if (arry[j + 1] >arry[j]) {
                    t = arry[j];
                    arry[j] = arry[j + 1];
                    arry[j + 1] = t;
                }
            }
        }
        for (int i=0;i<arry.length;i++) {
            System.out.println(i);
        }

    }
}

  

3.制作彩票35选7程序。 (就是1~35随机生成7个不重复的数)
package ssa;

import java.util.Random;


public class lianxi {
	public static void main(String[] args) {
       int a[] = new int[7];
        Random r = new Random();
        for (int i = 0; i < a.length; i++) {
            a[i] = r.nextInt(35)+1;
        }
        for (int x = 0; x < a.length; x++) {
            System.out.println(a[x]);
        }
 
    }
 
}

  

4.定义一个长度为10的int数组(如果没有特殊说明,静态赋值动态赋值都可以),统计数组中的最大值、最小值、以及奇 数和偶数的个数。
package ssa;

import java.util.Random;


public class lianxi {
	public static void main(String[] args) {
	int a[] = { 10, 20, 33, 34, 87, 90, 88, 9, 38, 44 }, q = 0;
		int o = 0, max = a[0], min = a[0];
		for (int i = 0; i < a.length; i++) {
			if (a[i] % 2 == 0) {
				o = o + 1;
			} else {
				q = q + 1;
			}
		}
		for (int x = 0; x < a.length; x++) {
			if (a[x] > max) {
				max = a[x];
			}
		}
		for (int y = 0; y < a.length; y++) {
			if (a[y] < min) {
				min = a[y];
			}
		}
		System.out.println("最大值是" + max + ",最小值是" + min + ",奇数有" + q + "个,偶数有" + o + "个");
	}

  

posted @ 2020-04-16 11:55  Libreation  阅读(129)  评论(0编辑  收藏  举报