1 #!/usr/bin/env/ python3
2 # -*- codinf: utf-8 -*-
3 # year: 2018
4 # day: 138
5 # --> XX/XX
6 # year: 2000
7 # day: 63
8 # --> 03/03
9 # year: 2014
10 # day: 63
11 # --> 03/04
12 def is_leap_year(year):
13 if year % 100 != 0:
14 if year % 4 == 0:
15 return 1
16 else:
17 if year % 400 == 0:
18 return 1
19 return 0
20
21 def get_days_by_year_month(year,month):
22 days = [ # 01 02 03 04 05 06 07 08 09 10 11 12
23 [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31],
24 [31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31],
25 ]
26 return days[is_leap_year(year)][month-1]
27
28 def get_month_day_by_year_days(year, days):
29 month, day = 1, 1
30 ###
31 while True:
32 d = get_days_by_year_month(year, month)
33 if days <= d:
34 day = days
35 break
36 days -= d
37 month += 1
38 ###
39
40 return month, day
41 def get_days_by_year_month_day(year, month, day):
42 # 2018/3/18 --> 31+28+18
43 days = day
44 for i in range(1, month):
45 days += get_days_by_year_month(year, i)
46 return days
47
48 if __name__ == '__main__':
49 year = int(input('year: '))
50 month = int(input('month: '))
51 day = int(input('day: '))
52 days = get_days_by_year_month_day(year, month, day)
53 print('%d/%02d/%02d --> %dday(s) in %d year.' %(year, month, day, days, year))
54 days = int(input('day: '))
55 month, day = get_month_day_by_year_days(year, days)
56 print('%d of %d --> %02d/%02d' %(days, year, month, day))
执行结果：
可以查询2018年开始到指定日期过去多少天，也可以用天数来查询日期
[root@lpc 05-4-日历]# python3 rili.py
year: 2018
month: 5
day: 27
2018/05/27 --> 147day(s) in 2018 year.
day: 148
148 of 2018 --> 05/28
