python——日历

#!/usr/bin/env/ python3
# -*- codinf: utf-8 -*-
# year: 2018
# day: 138
#   --> XX/XX
# year: 2000
# day: 63
# --> 03/03
# year: 2014
# day: 63
#   --> 03/04
def is_leap_year(year):
    if year % 100 != 0:
       if year % 4 == 0:
          return 1
    else:
       if year % 400 == 0:
          return 1
    return 0

def get_days_by_year_month(year,month):
    days = [ # 01  02  03  04  05  06  07  08  09 10 11 12
              [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31],
              [31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31],
    ]
    return days[is_leap_year(year)][month-1]

def get_month_day_by_year_days(year, days):
    month, day = 1, 1
    ###
    while True:
        d = get_days_by_year_month(year, month)
        if days <= d:
           day = days
           break
        days -= d
        month += 1
    ###

    return month, day
def get_days_by_year_month_day(year, month, day):
    # 2018/3/18  -->  31+28+18
    days = day
    for i in range(1, month):
        days += get_days_by_year_month(year, i)
    return days

if __name__ == '__main__':
    year  = int(input('year:  '))
    month = int(input('month: '))
    day   = int(input('day:   '))
    days  = get_days_by_year_month_day(year, month, day)
    print('%d/%02d/%02d --> %dday(s) in %d year.' %(year, month, day, days, year))
    days  = int(input('day: '))
    month, day = get_month_day_by_year_days(year, days)
    print('%d of %d --> %02d/%02d' %(days, year, month, day))

执行结果：

可以查询2018年开始到指定日期过去多少天，也可以用天数来查询日期
[root@lpc 05-4-日历]# python3 rili.py 
year:  2018
month: 5
day:   27
2018/05/27 --> 147day(s) in 2018 year.
day: 148
148 of 2018 --> 05/28