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MVC简捷调用EasyUI的datagrid

MVC简捷调用EasyUI的datagrid

一直想在项目中使用EasyUi的datagrid,但种种原因,没有实现。

这两天在开发一个项目中,愿望终于得以实现。

先看效果:

实现步骤是这样的:

1,在页面中画dataGrid,具体代码如下:

 View Code

<table id="UserListTb" class="easyui-datagrid" title="用户列表">
</table>

function ListLoad() {
var columnsSetting = [
{ field: 'EnName', title: '英文名', width: 100,sortable:true,
formatter: function (val, rowData) {
var url = "/User/Index/66666666";
return "<a href=\'" + url + "\');>"+rowData.EnName+"</a>";
}
},
{ field: 'CnName', title: '中文名', width: 80 },
{ field: 'DomainName', title: '域帐号', width: 120 },
{ field: 'ID', title: 'ID', width: 80, align: 'right' },
{ field: 'unitcost', title: '部门', width: 80, align: 'right' },
{ field: 'attr1', title: '权限组', width: 250 },
{ field: 'status', title: '状态', width: 60, align: 'center' }
];

$('#UserListTb').datagrid({
url: '/User/GetUserList',
queryParams: { name: "wuf"
},
method: 'get',
width: 1077,
height: 250,
fitColumns: true,
pagination: true,
pageSize: 20,
singleSelect: true,
showPageList: false,
pageList: [1,20, 50, 100],
rownumbers: true,
nowrap: false,
loadMsg: 'Load……',
columns: [columnsSetting],
onLoadSuccess: function (row) {},
onLoadError: function (arguments) {}
});
}

2,后台接收参数,返回需要的Json数据。

 View Code

/// <summary>
/// 用户列表Json
/// </summary>
/// <returns></returns>
public ActionResult GetUserList()
{
int currentPageIndex = RequestExtension.GetQueryString<int>("page", 0);
int pagesize = RequestExtension.GetQueryString<int>("rows", 0);
String sort = RequestExtension.GetQueryString<String>("sort", "");
String order = RequestExtension.GetQueryString<String>("order", "");

String name = RequestExtension.GetQueryString<String>("name", "");

Pagination pagin = new Pagination
{
CurrentPageIndex = currentPageIndex,
PageSize = pagesize,
OrderBy = String.IsNullOrEmpty(sort) ? "" : String.Concat(sort + " " + order)
};

UsersModel condition = new UsersModel();

KeyValuePair<Pagination, IList<UsersModel>> list = usersRepository.UsersPagination(pagin, condition);

return JsonExtension.JsonPagination(list.Value, pagin.CurrentPageIndex, pagin.PageSize, list.Key.TotalItemCount);
}

3,关键代码,实现Json分页的方法。

 View Code

/// <summary>
/// 分页处理
/// </summary>
/// <param name="dataList"></param>
/// <param name="page"></param>
/// <param name="rows"></param>
/// <returns></returns>
public static JsonResult JsonPagination(IEnumerable<dynamic> dataList, int page, int rows, int dataListAuctalCount = -1)
{
var result = dataList;
Dictionary<string, object> json = new Dictionary<string, object>();
int total = dataListAuctalCount;
if (total == -1 && dataList != null)
{
//自动分页
total = dataList.Count();
result = dataList.Skip((page - 1) * rows).Take(rows).ToList();
}
json.Add("total", total);
json.Add("rows", result);
return new JsonResult() { Data = json, JsonRequestBehavior = JsonRequestBehavior.AllowGet };
}

4,数据分页查询代码

 View Code

public KeyValuePair<Pagination, IList<UsersModel>> UsersPagination(Pagination pagin, UsersModel condition)
{
using (SqlConnection conn = DapperFactory.CrateOpenConnection())
{
String condtionStr = "";
String orderBy = "CreateTime DESC";
if (!String.IsNullOrEmpty(pagin.OrderBy))
{
orderBy = pagin.OrderBy;
}

String executeQuery = String.Format(@"WITH pagintable AS(
SELECT ROW_NUMBER() OVER(ORDER BY {1} )AS RowID, ID, DomainName, EnName, PassWord, CnName, Email, DeptID, RoleId, CreateMan, CreateTime, EditMan, EditTime, IsValid FROM Users
WHERE 1= 1 {0} )
SELECT * FROM pagintable where RowID between ((@CurrentPageIndex - 1) * @PageSize) + 1 and (@CurrentPageIndex * @PageSize)", condtionStr, orderBy);
String executeCount = String.Format("SELECT COUNT(*) AS CountNum FROM Users WHERE 1= 1 {0} ", condtionStr);
var mixCondition = new
{
CurrentPageIndex = pagin.CurrentPageIndex,
PageSize = pagin.PageSize
};
List<UsersModel> listScore = conn.Query<UsersModel>(executeQuery, mixCondition).ToList();
pagin.TotalItemCount = conn.Query<Int32>(executeCount, mixCondition).SingleOrDefault<Int32>();
KeyValuePair<Pagination, IList<UsersModel>> result =
new KeyValuePair<Pagination, IList<UsersModel>>(pagin, listScore);
return result;
}
}

看着这精简的代码,和界面上强大的功能,真是有种IT人的自豪感,亲爱的您,是不是也有这种感觉呢?

 

 
 
分类: EasyUI编程开发
posted on 2014-05-11 00:48  HackerVirus  阅读(311)  评论(0编辑  收藏  举报