Mincost
The cost of taking a taxi in Hangzhou is not a constant for each kilometer you travel: the first 4 kilometers costs 10 yuan (yuan is the monetary unit in China), even if you don't finish it; the next 4 kilometers costs 2 yuan each and the price for the rest of the trip is 2.4 yuan per kilometer; the last part of the trip is regarded as 1 kilometer even if it's shorter. A traveller may reduce the cost by reseting the meter at the middle of the trip if used wisely. For example, if the trip is 16 kilometers, he should cut it into two parts with the same length, each half will cost 18 yuan, with an overall cost of 36, less than the original price of 37.2. Now, given the length of the trip, find the minimum cost.
输入
The input contains several cases, each has one positive integer in a seperate line, representing the length of the trip. All input data are less than 10000000. Proceed until a case with zero, which should be ignored.
输出
For each case, output the minimum cost, leave one digit after decimal point if NECESSARY.
样例输入
3 9 16 0
样例输出
10 20.4 36
#include<stdio.h> #include<math.h> #include<string.h> int main() { //freopen("input.txt","r",stdin) double ans;int f; while(~scanf("%d",&f)&&f) { ans=0; if(f>0&&f<4)ans=10; else if(f>=4&&f<=8)ans=2+2*f; else { int k=f%8; ans=18*(f-k)/8; if(k<5) ans+=k*2.4; else ans+=10+(k-4)*2; } printf("%g\n",ans); } return 0; }
【推荐】还在用 ECharts 开发大屏?试试这款永久免费的开源 BI 工具!
【推荐】国内首个AI IDE,深度理解中文开发场景,立即下载体验Trae
【推荐】编程新体验,更懂你的AI,立即体验豆包MarsCode编程助手
【推荐】轻量又高性能的 SSH 工具 IShell:AI 加持,快人一步
· .NET 原生驾驭 AI 新基建实战系列:向量数据库的应用与畅想
· 从问题排查到源码分析:ActiveMQ消费端频繁日志刷屏的秘密
· 一次Java后端服务间歇性响应慢的问题排查记录
· dotnet 源代码生成器分析器入门
· ASP.NET Core 模型验证消息的本地化新姿势
· ThreeJs-16智慧城市项目(重磅以及未来发展ai)
· .NET 原生驾驭 AI 新基建实战系列(一):向量数据库的应用与畅想
· Ai满嘴顺口溜,想考研?浪费我几个小时
· Browser-use 详细介绍&使用文档
· 软件产品开发中常见的10个问题及处理方法