HD1046An Easy Task

Problem Description

Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?
Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.
Note: if year Y is a leap year, then the 1st leap year is year Y.

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains two positive integers Y and N(1<=N<=10000).

Output

For each test case, you should output the Nth leap year from year Y.

Sample Input

3 2005 25 1855 12 2004 10000

Sample Output

2108
1904
43236
Hint(We call year Y a leap year only if (Y%4==0 && Y%100!=0) or Y%400==0.)

水题,注意开始年如果也是瑞年的话,也要算一个:

#include<iostream>
using namespace std;
int main(){
    int n,a,b,count;
    cin>>n;
    while(n--){
        count=0;
        cin>>a>>b;
        while(count!=b)
        {
               a=a+0;
               if((a%4==0 && a%100!=0)||a%400==0)
               {count ++;}
               a++;
        }
        cout<<a-1<<endl;
    }
    return 0;
}
posted @ 2013-08-30 21:33  兰幽  阅读(203)  评论(0编辑  收藏  举报