from operator import itemgetter # itemgetter用来去dict中的key，省去了使用lambda函数
from itertools import groupby # itertool
d1={'name':'zhangsan','age':20,'country':'China'}
d2={'name':'wangwu','age':19,'country':'USA'}
d3={'name':'lisi','age':22,'country':'JP'}
d4={'name':'zhaoliu','age':22,'country':'USA'}
d5={'name':'pengqi','age':22,'country':'USA'}
d6={'name':'lijiu','age':22,'country':'China'}
lst=[d1,d2,d3,d4,d5,d6]
# 通过country进行分组：
lst.sort(key=itemgetter('country')) # 需要先排序，然后才能使用groupby
lstg = groupby(lst,itemgetter('country')) # 分组
# 等同于lstg = groupby(lst,key=lambda x:x['country'])
for country,items in lstg:
print(country)
for item in items:
print(item)
