C++交换两个数组的前n个字节

template<typename AnyType>
void TestSwapNData(AnyType* a,AnyType* b,int n)
{
    AnyType Temp;
    for (int i = 0; i < n; i++)
    {
        Temp = a[i];
        a[i] = b[i];
        b[i] = Temp;
    }
}

代码中，typename 可以替换成关键字class,两个关键字的效果是一样的

示例使用

int main()
{
    char buf1[10] = {0};
    char buf2[10] = {0};

    memcpy(buf1,"123456789",sizeof("123456789") );
    memcpy(buf2,"abcdefghi",sizeof("abcdefghi") );
    std::cout<<buf1<<std::endl<<buf2<<std::endl;

    TestSwapNData(buf1,buf2,5);
    std::cout<<buf1<<std::endl<<buf2<<std::endl;

    return 0;
}

运行结果显示：

PS:前两行是交换之前的数据，后两行是交换之后的数据