LeetCode - LRU cache

https://leetcode-cn.com/problems/lru-cache/

1. 支持查找,缓存不存在返回-1;存在的话,返回缓存的值,这里使用map存储缓存节点的映射关系,并且将缓存节点放置到最前端。

2. 支持快速删除,用双向链表来做删除。

#include <iostream>
#include <map>
using namespace std;

class CacheNode
{
public:
    CacheNode* pre;
    CacheNode* next;
    int k;
    int v;
    CacheNode(int k, int v):k(k),v(v)
    {
        pre = NULL;
        next = NULL;
    };
};

class LRUCache {
private:
    int cache_capacity;
    CacheNode* head;
    CacheNode* tail;
    int size;
    map<int, CacheNode*> cache_map;
public:
    LRUCache(int capacity)
    {
        head = NULL;
        tail = NULL;
        cache_capacity = capacity;
        size = 0;
    }

    int getNode(int key) {
        //get cache node ptr
        int ret = 0;
        if(cache_map.find(key) == cache_map.end())
        {
            return -1;
        }
        ret = cache_map[key]->v;
        removeNode(key);
        addNode(key,ret);
        return ret;
    }

    int get(int key) {
        // cout<<getNode(key)<<endl;
        // Print();
        return getNode(key);
    }

    void removeNode(int key)
    {
        if(cache_map.find(key) == cache_map.end() || size <= 0)
            return;

        size--;
        map<int, CacheNode*>::iterator iter = cache_map.find(key);
        CacheNode* cn = iter->second;
        cache_map.erase(iter);

        if(cn->next){
            cn->next->pre = cn->pre;
        }
        if(cn->pre)
        {
            cn->pre->next = cn->next;
        }
        if(cn == head)
        {
            head = head->next;
        }
        if(cn == tail)
        {
            tail = tail->pre;
        }

        delete cn;
        return;
    }

    void addNode(int key, int value)
    {
        size++;
        CacheNode* p = new CacheNode(key,value);
        cache_map[key] = p;
        if(size == 1)
        {
            head = p;
            tail = p;
            tail->next = NULL;
            head->pre = NULL;
        }
        else
        {
            p->next = head;
            head->pre = p;
            head = p;
        }
        return;
    }

    void put(int key, int value)
    {
        //if exist
        if(cache_map.find(key) != cache_map.end())
        {
            removeNode(key);
            addNode(key,value);
        }
        else
        {
            if(size < cache_capacity)
            {
                addNode(key,value);
            }
            else
            {
                //del tail
                removeNode(tail->k);
                addNode(key,value);
            }
        }
    }
};



int main()
{
    LRUCache* cache_ptr = new LRUCache(2);
    LRUCache cache = *cache_ptr;
    cache.put(2, 1);
    cache.put(3,2);
    cache.get(3);       // 返回  2
    cache.get(2);       // 返回  1
    cache.put(4, 3);    // 该操作会使得关键字 3 作废
    cache.get(2);       // 返回  1
    cache.get(3);       // 返回  -1
    cache.get(4);       // 返回  3
    return 0;
}

 

#include <iostream>
#include <map>
using namespace std;

class CacheNode
{
public:
    CacheNode* pre;
    CacheNode* next;
    int k;
    int v;
    CacheNode(int kint v):k(k),v(v)
    {
        pre = NULL;
        next = NULL;
    };
};

class LRUCache {
private:
    int cache_capacity;
    CacheNode* head;
    CacheNode* tail;
    int size;
    map<int, CacheNode*> cache_map;
public:
    LRUCache(int capacity)
    {
        head = NULL;
        tail = NULL;
        cache_capacity = capacity;
        size = 0;
    }

    int getNode(int key) {
        //get cache node ptr
        int ret = 0;
        if(cache_map.find(key) == cache_map.end())
        {
            return -1;
        }
        ret = cache_map[key]->v;
        removeNode(key);
        addNode(key,ret);
        return ret;
    }

    int get(int key) {
        // cout<<getNode(key)<<endl;
        // Print();
        return getNode(key);
    }

    void removeNode(int key)
    {
        if(cache_map.find(key) == cache_map.end() || size <= 0)
            return;

        size--;
        map<intCacheNode*>::iterator iter = cache_map.find(key);
        CacheNode* cn = iter->second;
        cache_map.erase(iter);

        if(cn->next){
            cn->next->pre = cn->pre;
        }
        if(cn->pre)
        {
            cn->pre->next = cn->next;
        }
        if(cn == head)
        {
            head = head->next;
        }
        if(cn == tail)
        {
            tail = tail->pre;
        }

        delete cn;
        return;
    }

    void addNode(int keyint value)
    {
        size++;
        CacheNode* p = new CacheNode(key,value);
        cache_map[key] = p;
        if(size == 1)
        {
            head = p;
            tail = p;
            tail->next = NULL;
            head->pre = NULL;
        }
        else
        {
            p->next = head;
            head->pre = p;
            head = p;
        }
        return;
    }

    void put(int keyint value)
    {
        //if exist
        if(cache_map.find(key) != cache_map.end())
        {
            removeNode(key);
            addNode(key,value);
        }
        else
        {
            if(size < cache_capacity)
            {
                addNode(key,value);
            }
            else
            {
                //del tail
                removeNode(tail->k);
                addNode(key,value);
            }
        }
    }
};



int main()
{
    LRUCache* cache_ptr = new LRUCache(2);
    LRUCache cache = *cache_ptr;
    cache.put(21);
    cache.put(3,2);
    cache.get(3);       // 返回  2
    cache.get(2);       // 返回  1
    cache.put(43);    // 该操作会使得关键字 3 作废
    cache.get(2);       // 返回  1
    cache.get(3);       // 返回  -1
    cache.get(4);       // 返回  3
    return 0;
}
posted @ 2020-06-29 21:24  0giant  阅读(193)  评论(0编辑  收藏  举报