摘要: public async Task Test(int i) { await Task.Run(()=>testFunc(i)); return Json("请求成功",JsonRequestBehavior.AllowGet); } public async Task testFunc(int i) ... 阅读全文
posted @ 2019-03-04 10:43 Super-Yan 阅读(99) 评论(0) 推荐(0) 编辑