hdu 1398 Square Coins/hdu 1028 Ignatius and the Princess III

两道母函数的模板题：

http://acm.hdu.edu.cn/showproblem.php?pid=1398

#include<iostream>
#include<cstdio>
using namespace std;
int c1[310],c2[310];
int main()
{
    int n,i,j,k;
    while(scanf("%d",&n),n)
    {
        for(i=0;i<=n;i++)
        {
            c1[i]=1;
            c2[i]=0;
        }
        for(i=2;i*i<=n;i++)
        {
        for(j=0;j<=n;j++)
        for(k=0;k+j<=n;k+=i*i)
        c2[k+j]+=c1[j];
        for(j=0;j<=n;j++)
        {
            c1[j]=c2[j];
            c2[j]=0;
        }
        }
        printf("%d\n",c1[n]);
    }
    return 0;
}

http://acm.hdu.edu.cn/showproblem.php?pid=1028

#include<iostream>
#include<cstdio>
using namespace std;
int c1[130],c2[130];
int main()
{
    int n,i,j,k;
    while(scanf("%d",&n)!=EOF)
    {
        for(i=0;i<=n;i++)
        {
            c1[i]=1;
            c2[i]=0;
        }
        for(i=2;i<=n;i++)
        {
        for(j=0;j<=n;j++)
        for(k=0;k+j<=n;k+=i)
        c2[k+j]+=c1[j];
        for(j=0;j<=n;j++)
        {
            c1[j]=c2[j];
            c2[j]=0;
        }
        }
        printf("%d\n",c1[n]);
    }
    return 0;
}