UVA 113

Power of Cryptography 

Background

Current work in cryptography involves (among other things) large prime numbers and computing powers of numbers modulo functions of these primes.  Work in this area has resulted in the practical use of results from number theory and other branches of mathematics once considered to be of only theoretical interest.

This problem involves the efficient computation of integer roots of numbers.

The Problem

Given an integer  tex2html_wrap_inline32  and an integer  tex2html_wrap_inline34  you are to write a program that determines  tex2html_wrap_inline36 , the positive  tex2html_wrap_inline38  root of p.  In this problem, given such integers n and p, p will always be of the form  tex2html_wrap_inline48  for an integer k (this integer is what your program must find).

The Input

The input consists of a sequence of integer pairs n and p with each integer on a line by itself.  For all such pairs  tex2html_wrap_inline56tex2html_wrap_inline58  and there exists an integer ktex2html_wrap_inline62  such that  tex2html_wrap_inline64 .

The Output

For each integer pair n and p the value  tex2html_wrap_inline36  should be printed, i.e., the number k such that  tex2html_wrap_inline64 .

Sample Input

2
16
3
27
7
4357186184021382204544

Sample Output

4
3
1234
水题一个,最主要的问题就是数据量的控制,这里用的是double,其实long double应该也可以,还没有尝试,总之看代码吧:
#include<stdio.h>
#include<math.h>

int main()
 {
  double n, p;
  while(scanf("%lf%lf", &n, &p) != EOF)
  {
   printf("%.0lf\n", pow(p, 1/n));
  }
  return 0;
 }
View Code

 

posted on 2013-07-17 23:23  Forgiving  阅读(98)  评论(0编辑  收藏  举报