SSCTF2020 RE2

SSCTF2020 RE2

有时间做了一下SSCTF 2020的re2

附件地址:

链接:https://pan.baidu.com/s/1k5SuiJIHJzgYZVbc9hX8ZA
提取码:lyco

基本方法:动调

int sub_8310A0()
{
  HANDLE v0; // esi
  HMODULE v1; // eax
  FARPROC v2; // eax
  unsigned int v3; // ebx
  __int64 v4; // rdi
  signed int v5; // kr08_4
  unsigned int v6; // ecx
  unsigned int v7; // edx
  unsigned int v8; // eax
  unsigned int v9; // ecx
  int v10; // eax
  int v11; // edx
  unsigned int v12; // ecx
  char v13; // al
  bool v14; // cf
  unsigned int v15; // ecx
  const char *v16; // eax
  int v17; // eax
  int v18; // edx
  char v19; // cl
  int v20; // edx
  char v21; // ch
  int v22; // eax
  char v23; // cl
  int v24; // eax
  int v25; // edx
  char v26; // ch
  char v27; // cl
  int v28; // kr28_4
  signed int v29; // ecx
  unsigned int v30; // ebx
  unsigned int v31; // edi
  unsigned int v32; // ecx
  unsigned int v33; // eax
  char v35; // [esp+13h] [ebp-125h]
  char v36; // [esp+13h] [ebp-125h]
  unsigned int v37; // [esp+14h] [ebp-124h]
  int v38; // [esp+14h] [ebp-124h]
  int v39; // [esp+18h] [ebp-120h]
  char *v40; // [esp+1Ch] [ebp-11Ch]
  unsigned int v41; // [esp+20h] [ebp-118h]
  signed int v42; // [esp+2Ch] [ebp-10Ch]
  int v43; // [esp+30h] [ebp-108h]
  int v44; // [esp+34h] [ebp-104h]
  int v45; // [esp+38h] [ebp-100h]
  int v46; // [esp+3Ch] [ebp-FCh]
  int v47; // [esp+40h] [ebp-F8h]
  int v48; // [esp+44h] [ebp-F4h]
  __int64 v49; // [esp+48h] [ebp-F0h]
  int v50; // [esp+50h] [ebp-E8h]
  int v51; // [esp+54h] [ebp-E4h]
  char *v52; // [esp+58h] [ebp-E0h]
  int v53; // [esp+64h] [ebp-D4h]
  char v54; // [esp+68h] [ebp-D0h]
  char v55; // [esp+69h] [ebp-CFh]
  char v56[202]; // [esp+6Ah] [ebp-CEh]

  sub_832260((__m128i *)&v54, 0, 0xC8u);
  v43 = 0x3B082235;
  v44 = 0xFCF20A00;
  v45 = 0xE2EED037;
  v46 = 0xF3FEFAD6;
  v47 = 0xC2101FF5;
  v48 = 0xD703FBEC;
  v49 = 0xE029FC16FCC9E2FCi64;
  v50 = 0xFE1134F0;
  LOWORD(v51) = 0x2761;
  BYTE2(v51) = 39;
  v0 = GetCurrentThread();
  v1 = LoadLibraryA("ntdll.dll");
  v2 = GetProcAddress(v1, "ZwSetInformationThread");// 反调试,直接修改EIP绕过
  ((void (__stdcall *)(HANDLE, signed int, _DWORD, _DWORD))v2)(v0, 17, 0, 0);
  sub_831020((int)"Pls Input Your Flag:");
  sub_831060("%s", &v54, 39);
  v3 = (signed int)&v54 >> 31;
  HIDWORD(v4) = &v54;
  LODWORD(v4) = &v54;
  v52 = &v54;
  v40 = &v54;
  v5 = strlen(&v54);
  v53 = v5;
  if ( v5 > 0 )
  {
    v6 = 0;
    v37 = 0;
    v41 = 0;
    do
    {
      do
      {
        v7 = v37;
        v8 = v41 - 7 * (v6 / 7);
        v9 = v41;
        *(&v54 + v41) = (*(&v54 + v41) ^ aDdxtqkl[v8]) + 65;// 进行第一次加密,即将输入与对应字符串进行取余异或加65
        v10 = v41++;
        v37 = (__PAIR__(v37, v9) + 1) >> 32;
        v6 = v9 + 1;
      }
      while ( v5 - 1 != v10 );
    }
    while ( v7 );
    v38 = 0;
    HIDWORD(v4) = (signed int)&v54 >> 31;
    do
    {
      v35 = *(_BYTE *)(v4 + 3);
      v11 = (unsigned __int64)(v4 + 3) >> 32;
      v12 = v4 + 3;
      LODWORD(v4) = v4 + 3;
      do
      {
        v13 = *(_BYTE *)(v4 - 1);
        v14 = v12-- != 0;                       // 第二次加密,即分组,每组四位 将每组第四位放在第一位,前三个顺延,即1->2,2->3,3->4
        LODWORD(v4) = v12;
        v11 = v14 + v11 - 1;
        *(_BYTE *)(v12 + 1) = v13;
      }
      while ( __PAIR__(HIDWORD(v4), v12) != __PAIR__(v11, (unsigned int)v40) );
      LODWORD(v4) = v40;
      v38 += 4;
      *v40 = v35;
      v40 += 4;
      v4 += 4i64;
    }
    while ( v53 > v38 );
    HIDWORD(v4) = v52;
    v3 = (signed int)&v54 >> 31;
  }
  v15 = 0;
  while ( *((_BYTE *)&v43 + v15) == ((unsigned __int8)*(&v54 + v15) ^ 0x61) )// change[0]^0x61与v43[0]
  {
    if ( *((_BYTE *)&v43 + v15 + 1) != ((unsigned __int8)*(&v55 + v15) ^ 0x61) )// change[1]^0x61与v43[1]
    {
      ++v15;
      break;
    }
    if ( *((_BYTE *)&v43 + v15 + 2) != ((unsigned __int8)v56[v15] ^ 0x61) )// change[2]^0x61与v43[2]
    {
      v15 += 2;
      break;
    }
    v15 += 3;
    if ( v15 >= 39 )
      break;
  }
  v16 = "wtf?\n";
  if ( v15 == 39 )
    v16 = "you got it!\n";
  sub_831020((int)v16);
  sub_8395C1("pause");
  v42 = 10;
  do
  {
    v36 = *(_BYTE *)(HIDWORD(v4) + 3);
    LODWORD(v4) = HIDWORD(v4) + 3;
    v17 = __CFADD__(HIDWORD(v4), 3) + v3;
    v18 = HIDWORD(v4) + 3;
    do
    {
      v19 = *(_BYTE *)(v18 - 1);
      v14 = (_DWORD)v4 != 0;
      LODWORD(v4) = v4 - 1;
      v18 = v4;
      v17 = v14 + v17 - 1;
      *(_BYTE *)(v4 + 1) = v19;
    }
    while ( __PAIR__(HIDWORD(v4), v3) != __PAIR__(v4, v17) );
    LODWORD(v4) = HIDWORD(v4) + 3;
    v20 = HIDWORD(v4) + 3;
    *(_BYTE *)HIDWORD(v4) = v36;
    v21 = *(_BYTE *)(HIDWORD(v4) + 3);
    v22 = __CFADD__(HIDWORD(v4), 3) + v3;
    do
    {
      v23 = *(_BYTE *)(v20 - 1);
      v14 = (_DWORD)v4 != 0;
      LODWORD(v4) = v4 - 1;
      v20 = v4;
      v22 = v14 + v22 - 1;
      *(_BYTE *)(v4 + 1) = v23;
    }
    while ( __PAIR__(HIDWORD(v4), v3) != __PAIR__(v4, v22) );
    v24 = HIDWORD(v4) + 3;
    v25 = __CFADD__(HIDWORD(v4), 3) + v3;
    LODWORD(v4) = HIDWORD(v4) + 3;
    *(_BYTE *)HIDWORD(v4) = v21;
    v26 = *(_BYTE *)(HIDWORD(v4) + 3);
    do
    {
      do
      {
        v27 = *(_BYTE *)(v4 - 1);
        v14 = v24-- != 0;
        LODWORD(v4) = v24;
        v25 = v14 + v25 - 1;
        *(_BYTE *)(v24 + 1) = v27;
      }
      while ( HIDWORD(v4) != v24 );
    }
    while ( v3 != v25 );
    *(_BYTE *)HIDWORD(v4) = v26;
    v28 = HIDWORD(v4) + 4;
    v3 = (__PAIR__(v3, HIDWORD(v4)) + 4) >> 32;
    HIDWORD(v4) += 4;
    --v42;
  }
  while ( v42 );
  v29 = strlen((const char *)(v28 - 40));
  if ( v29 > 0 )
  {
    *(_QWORD *)&v52 = 0i64;
    v30 = 0;
    v31 = 0;
    v39 = v29 - 1;
    do
    {
      do
      {
        v32 = v30;
        *(_BYTE 
          
          *)(v31 + v28 - 40) = aDdxtqkl[v31 % 7] ^ (*(_BYTE *)(v31 + v28 - 40) - 65);
        v33 = v31;
        v30 = (__PAIR__(v30, v31++) + 1) >> 32;
      }
      while ( v39 != v33 );
    }
    while ( v32 );
  }
  return 0;
}

最底下的迷惑语句不需要管,找到出口就行

#include <stdio.h>
#include <string.h>

int main()
{
    char s[]="dDxtQkl";
    
    unsigned char ida_chars[] =
{
  0x35, 0x22, 0x08, 0x3B, 0x00, 0x0A, 0xF2, 0xFC, 0x37, 0xD0, 
  0xEE, 0xE2, 0xD6, 0xFA, 0xFE, 0xF3, 0xF5, 0x1F, 0x10, 0xC2, 
  0xEC, 0xFB, 0x03, 0xD7, 0xFC, 0xE2, 0xC9, 0xFC, 0x16, 0xFC, 
  0x29, 0xE0, 0xF0, 0x34, 0x11, 0xFE,0x61,0x27,0x27
};
    int i=0;
    int j=0,tmp;
    for(i=0;i<39;i++){
        ida_chars[i]^=0x61;
    }

    for(i=0;i<39;i=i+4){
        tmp=ida_chars[i];
        ida_chars[i]=ida_chars[i+1];
        ida_chars[i+1]=ida_chars[i+2];
        ida_chars[i+2]=ida_chars[i+3];
        ida_chars[i+3]=tmp;
    }
    for(i=0;i<39;i++){
        printf("%c",(ida_chars[i]-65)^s[i%7]);
    }
    return 0;
}

posted @ 2020-11-13 11:31  LLeaves  阅读(144)  评论(0编辑  收藏  举报