The Same Game(模拟)

http://poj.org/problem?id=1027

题意:给一个10*15的地图,里面填充R,G,B三种颜色,每次找到当前地图的同色最大区域M,并将其删除,删除M后,上面的小球自然下落,当有空列时,空列右边的小球同时向左移动一列,

        当最后地图上同色最大区域的小球个数是1或0时,循环结束;注意输出格式,最后输出一个空行。

思路:

while(true)

{

  找到同色最大区域,包括其面积Maxsize,坐标,颜色(BFS,手写队列);

  if (Maxsize == 1 || Maxsize == 0) break;

  删除该最大区域,即将map[i][j] 置为0,(BFS,手写队列);

  重置地图;

  输出;

 

  1 #include<stdio.h>
  2 #include<string.h>
  3 char map[20][20];
  4 bool vis[20][20];
  5 int MaxR,MaxC;//分别存同色最大区域左下角坐标
  6 int Maxsize;//Maxsize存最大面积
  7 char Maxcolor;//最大同色区域的颜色;
  8 
  9 int Area(int i,int j)//搜索当前同色区域面积
 10 {
 11     struct node
 12     {
 13         int x,y;
 14     }que[160];
 15 
 16     int head,tail;
 17     head = tail = 0;
 18 
 19     que[tail].x = i;
 20     que[tail++].y = j;
 21     vis[i][j] = true;
 22 
 23     char color = map[i][j];
 24     int size = 0;
 25     while(head < tail)
 26     {
 27         int x = que[head].x;
 28         int y = que[head++].y;
 29         size++;
 30 
 31         if((x+1)<10 && !vis[x+1][y] && map[x+1][y] == color)
 32         {
 33             que[tail].x = x+1;
 34             que[tail++].y = y;
 35             vis[x+1][y] = true;
 36         }
 37         if((x-1)>=0 && !vis[x-1][y] && map[x-1][y] == color)
 38         {
 39             que[tail].x = x-1;
 40             que[tail++].y = y;
 41             vis[x-1][y] = true;
 42         }
 43         if((y-1)>=0 && !vis[x][y-1] && map[x][y-1] == color)
 44         {
 45             que[tail].x = x;
 46             que[tail++].y = y-1;
 47             vis[x][y-1] = true;
 48         }
 49         if((y+1)<15 && !vis[x][y+1] && map[x][y+1] == color)
 50         {
 51             que[tail].x = x;
 52             que[tail++].y = y+1;
 53             vis[x][y+1] = true;
 54         }
 55     }
 56     return size;
 57 }
 58 
 59 void SearchArea()//搜索同色最大区域;
 60 {
 61     int i,j;
 62     memset(vis,false,sizeof(vis));
 63     Maxsize = 0;
 64     for(j = 0; j < 15; j++)
 65     {
 66         for(i = 0; i < 10; i++)
 67         {
 68             int size = -1;
 69             if(!vis[i][j] && map[i][j])
 70             {
 71                 size = Area(i,j);
 72                 if(size > Maxsize)
 73                 {
 74                     Maxsize = size;
 75                     MaxR = i;
 76                     MaxC = j;
 77                     Maxcolor = map[MaxR][MaxC];
 78                 }
 79             }
 80         }
 81     }
 82 }
 83 
 84 
 85 void DelArea()//删除最大区域
 86 {
 87     struct node
 88     {
 89         int x,y;
 90     }que[160];
 91     int head,tail;
 92     head = tail = 0;
 93     que[tail].x = MaxR;
 94     que[tail++].y = MaxC;
 95 
 96     Maxcolor = map[MaxR][MaxC];
 97     map[MaxR][MaxC] = 0;
 98 
 99     while(head < tail)
100     {
101         int x = que[head].x;
102         int y = que[head++].y;
103         map[x][y] = 0;
104 
105         if(x+1 < 10 && map[x+1][y] == Maxcolor)
106         {
107             map[x+1][y] = 0;
108             que[tail].x = x+1;
109             que[tail++].y = y;
110         }
111         if(x-1 >= 0 && map[x-1][y] == Maxcolor)
112         {
113             map[x-1][y] = 0;
114             que[tail].x = x-1;
115             que[tail++].y = y;
116         }
117         if(y-1 >= 0 && map[x][y-1] == Maxcolor)
118         {
119             map[x][y-1] = 0;
120             que[tail].x = x;
121             que[tail++].y = y-1;
122         }
123         if(y+1 < 15 && map[x][y+1] == Maxcolor)
124         {
125             map[x][y+1] = 0;
126             que[tail].x = x;
127             que[tail++].y = y+1;
128         }
129     }
130 }
131 
132 void NewMap()//重置
133 {
134     bool empty[15] = {false};//记录哪一列是空列
135     int i,j;
136     for(j = 0; j < 15; j++)//重置行
137     {
138         int ti = -1;//表示第ti行是空的,ti = -1 表示现在没有空行;
139         bool flag = false;
140         for(i = 0; i < 10; i++)
141         {
142             if(map[i][j])
143             {
144                 flag = true;
145                 if(ti != -1)
146                 {
147                     map[ti][j] = map[i][j];//将第i行移至第ti行
148                     map[i][j] = 0;//将第i行置0;
149                     i = ti;//从ti行开始再一次枚举;
150                     ti = -1;
151                 }
152             }
153             else
154             {
155                 ti = i;
156                 while(i+1 < 10 && !map[i+1][j])
157                     i++;
158             }
159         }
160         if(!flag)
161             empty[j] = true;
162     }
163     int tj = -1;//表示第tj列是空的,tj = -1说明现在好没有空列
164     for(j = 0; j < 15; j++)//重置列
165     {
166         if(!empty[j])//如果第j列是不空的
167         {
168             if(tj != -1)
169             {
170                 for(i = 0; i < 10; i++)
171                 {
172                     map[i][tj] = map[i][j];
173                     map[i][j] = 0;
174                 }
175                 empty[j] = true;
176                 j = tj;
177                 tj = -1;
178             }
179         }
180         else
181         {
182             tj = j;
183             while(j+1<15 && empty[j+1])
184                 j++;
185         }
186     }
187 }
188 
189 int main()
190 {
191     int test;
192     scanf("%d",&test);
193     for(int item = 1; item <= test; item++)
194     {
195         for(int i = 9; i >= 0; i--)
196             scanf("%s",map[i]);
197 
198         printf("Game %d:\n\n",item);
199 
200         int Balls = 150;
201         int step = 0;
202         int sumscore = 0;
203         while(true)
204         {
205             Maxsize = -1;
206             SearchArea();//寻找同色最大区域;
207             if(Maxsize == 0 || Maxsize == 1)
208                 break;
209 
210             DelArea();//删除当前最大区域
211             NewMap();//重置
212 
213             int score = (Maxsize-2)*(Maxsize-2);
214             printf("Move %d at (%d,%d): removed %d balls of color %c, got %d points.\n",++step,MaxR+1,MaxC+1,Maxsize,Maxcolor,score);
215             Balls = Balls - Maxsize;
216             sumscore += score;
217         }
218         if(Balls == 0)
219             sumscore += 1000;
220         printf("Final score: %d, with %d balls remaining.\n\n",sumscore,Balls);
221     }
222     return 0;
223 }
View Code

 

 

posted on 2013-11-05 20:54  straw_berry  阅读(231)  评论(0编辑  收藏  举报