熟悉的A+B

读入两个小于100的正整数A和B,计算A+B. 需要注意的是:A和B的每一位数字由对应的英文单词给出.

 

Input

测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出.

 

Output

对每个测试用例输出1行,即A+B的值.

 

Sample Input

one + two = three four + five six = zero seven + eight nine = zero + zero =

 

Sample Output

3 90 96

#include<stdio.h>
#include<string.h>
int cmp(char s[])
{
    if(strcmp(s,"zero") ==0 ) return 0;
    else if(strcmp(s,"one") ==0 ) return 1;
    else if(strcmp(s,"two") == 0) return 2;
    else if(strcmp(s,"three") == 0) return 3;
    else if(strcmp(s,"four") == 0) return 4;
    else if(strcmp(s,"five") == 0) return 5;
    else if(strcmp(s,"six") == 0) return 6;
    else if(strcmp(s,"seven") == 0) return 7;
    else if(strcmp(s,"eight") == 0) return 8;
    else if(strcmp(s,"nine") == 0) return 9;
    return 0;

}
int main ()
{
    char s[10];
    int cnt = 0, i = 10, sum = 0, tmp = 0;因为题目说两位数之内，令i为10
    while(~scanf("%s",s))用scanf读入。
    {
        if(strcmp(s,"+") == 0)
        {
            if(cnt == 1)
                sum = tmp/10;如果加号前只有一个数，则加上temp/10;
            else if(cnt == 2)
                sum = tmp;
            cnt = 0;
            i = 10;
            tmp = 0;重置

        }
        else if(strcmp(s,"=") == 0)
        {
            if(cnt == 1)
                sum += tmp/10;
            else if(cnt == 2)
                sum += tmp;
            if(sum == 0)
                return 0;读入结束
            else printf("%d\n",sum);
            sum = 0;
            i = 10;
            cnt = 0;
            tmp = 0;
        }
        else
        {
            cnt++;表示有几个数
            tmp += cmp(s)*i;
            i = i/10;
        }
    }
    return 0;
}