2016huasacm暑假集训训练五 H - Coins

题目链接：https://vjudge.net/contest/126708#problem/H

题意：A有一大堆的硬币，他觉得太重了，想花掉硬币去坐的士；的士司机可以不找零，但是的士司机也不会多收零钱。怎么样才能使 A 花的零钱最多。

多重背包模板题

AC代码：

 1 import java.io.BufferedReader;
 2 import java.io.IOException;
 3 import java.io.InputStream;
 4 import java.io.InputStreamReader;
 5 import java.util.Arrays;
 6 import java.util.StringTokenizer;
 7 public class Main{
 8   public static void main(String args[])
 9 {
10    int N, M;
11    Scanner sc=new Scanner(System.in);
12    while(sc.hasNext())
13    {
14       N=sc.nextInt(); 
15       M=sc.nextInt(); 
16       if(N==0&&M==0) break;
17       int a[]=new int[105]; 
18       int c[]=new int [105]; 
19       int u[]=new int[100001];
20       for (int i=0; i< N; i++) a[i]=sc.nextInt();
21       for (int i=0; i< N; i++) c[i]=sc.nextInt();
22       int sun=0;
23       boolean s[]=new boolean[100001];
24       s[0]=true;
25 
26       for (int i=0; i< N; i++)
27       {
28          Arrays.fill(u, 0);
29           for (int j=a[i]; j<=M; j++)
30           {
31              if (!s[j] && s[j-a[i]] && u[j-a[i]]< c[i])
32               {
33                    s[j]=true;
34                    u[j]=u[j-a[i]]+1;
35                    sun++;
36               }
37           }
38       }
39       System.out.println(sun);
40    }
41     
42   } 
43 }
44 class Scanner {
45     BufferedReader br;
46     StringTokenizer st;
47 
48     Scanner(InputStream in) {
49         br = new BufferedReader(new InputStreamReader(in));
50         eat("");
51     }
52 
53     private void eat(String string) {
54         st = new StringTokenizer(string);
55     }
56 
57     String nextLine() {
58         try {
59             return br.readLine();
60         } catch (IOException e) {
61             return null;
62         }
63     }
64 
65     boolean hasNext() {
66         while (!st.hasMoreTokens()) {
67             String s = nextLine();
68             if (s == null)
69                 return false;
70             eat(s);
71         }
72         return true;
73     }
74 
75     String next() {
76         hasNext();
77         return st.nextToken();
78     }
79 
80     int nextInt() {
81         return Integer.parseInt(next());
82     }
83        
84     long nextLong() {
85         return Long.parseLong(next());
86     }
87 
88     double nextDouble() {
89         return Double.parseDouble(next());
90     }
91 }

 

posted @ 2016-08-10 16:03  Geek.w  阅读(418)  评论(0)  编辑  收藏  举报