摘要: strstr(str1,str2) 函数用于判断字符串str2是否是str1的子串。如果是,则该函数返回str2在str1中首次出现的地址;否则,返回NULL。 头文件: <cstring> 源码: 阅读全文
posted @ 2016-09-13 21:47 Kiven#5197 阅读(320) 评论(0) 推荐(0) 编辑
摘要: Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 2390 Accepted Submission(s): 746 Problem Descript 阅读全文
posted @ 2016-09-13 21:44 Kiven#5197 阅读(205) 评论(0) 推荐(0) 编辑
摘要: Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 1100 Accepted Submission(s): 674 Problem Descri 阅读全文
posted @ 2016-09-13 21:38 Kiven#5197 阅读(301) 评论(0) 推荐(0) 编辑
摘要: Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 1175 Accepted Submission(s): 643 Problem Descri 阅读全文
posted @ 2016-09-13 21:32 Kiven#5197 阅读(307) 评论(0) 推荐(0) 编辑
摘要: Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 2865 Accepted Submission(s): 719 Problem Descri 阅读全文
posted @ 2016-09-13 21:27 Kiven#5197 阅读(323) 评论(0) 推荐(0) 编辑