UVA 11475 Extend to Palindrome(hash)题解
题意:问你最少加几个字母使所给串变成回文串。
思路:一开始打算将正序和逆序都hash,然后用提取前缀后缀的方法来找,但是RE了,debug失败遂弃之。后来发现可以直接hash,一边hash一边比较。我们只需找出正序hash值和逆序hash相同的最长串就是最长回文子串。
代码:
#include<stack> #include<vector> #include<queue> #include<set> #include<cstring> #include<string> #include<sstream> #include<iostream> #include<cstdio> #include<cmath> #include<algorithm> #define ll long long #define ull unsigned long long using namespace std; const int maxn = 200000+10; const int seed = 131; const int MOD = 100013; const int INF = 0x3f3f3f3f; char s[maxn]; int main(){ while(scanf("%s", s + 1) != EOF){ int len = strlen(s + 1); ull suf = 0,pre = 0,bit = 1,Max = 1; for(int i = len; i >= 1; i--){ pre = pre * seed + s[i]; //倒序前缀 if(i != len) bit *= seed; suf = suf + bit * s[i]; //正序后缀 if(pre == suf){ Max = len - i + 1; } } for(int i = 1; i <= len; i++) printf("%c", s[i]); for(int i = len - Max; i >= 1; i--) printf("%c", s[i]); printf("\n"); } return 0; } /* aaaa abba amanaplanacanal xyz */