摘要: 1 //n个方程,x=a[i](mod m[i]) 2 3 LL china(int n, int *a, int *m) { 4 LL M = 1, d, y, x = 0; 5 for(int i = 0; i < n; i++) M *= m[i]; 6 for(int i = 0; i < n' i++) { 7 LL w = ... 阅读全文
posted @ 2016-09-05 11:23 kiraa 阅读(128) 评论(0) 推荐(0) 编辑