09 2016 档案

摘要:1 //求解模方程 a^x = b(mod n) n为素数,无解返回-1 2 int log_mod(int a, int b, int n) { 3 int m, v, e = 1, i; 4 m = (int) sqrt(n+0.5); 5 v = inv(pow_mod(a, m, n), n); 6 map x; 7 x[1] = ... 阅读全文
posted @ 2016-09-07 12:29 kiraa 阅读(493) 评论(0) 推荐(0)
摘要:1 //n个方程,x=a[i](mod m[i]) 2 3 LL china(int n, int *a, int *m) { 4 LL M = 1, d, y, x = 0; 5 for(int i = 0; i < n; i++) M *= m[i]; 6 for(int i = 0; i < n' i++) { 7 LL w = ... 阅读全文
posted @ 2016-09-05 11:23 kiraa 阅读(136) 评论(0) 推荐(0)