SMU 2024 spring 天梯赛自主训练1

SMU 2024 spring 天梯赛自主训练1

7-1 宇宙无敌大招呼 - SMU 2024 spring 天梯赛自主训练1 (pintia.cn)

#include <bits/stdc++.h>
#define debug(a) cout<<#a<<"="<<a<<'\n';

using namespace std;
using i64 = long long;

typedef pair<i64, i64> PII;

int main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);

	string s;
	cin >> s;
	cout << "Hello " << s << '\n';

	return 0;
}

7-2 日期格式化 - SMU 2024 spring 天梯赛自主训练1 (pintia.cn)

#include <bits/stdc++.h>
#define debug(a) cout<<#a<<"="<<a<<'\n';

using namespace std;
using i64 = long long;

typedef pair<i64, i64> PII;

int main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);

	int m,d,y;
	scanf("%d-%d-%d",&m,&d,&y);
	printf("%d-%02d-%02d\n",y,m,d);

	return 0;
}

7-3 寻找250 - SMU 2024 spring 天梯赛自主训练1 (pintia.cn)

#include <bits/stdc++.h>
#define debug(a) cout<<#a<<"="<<a<<'\n';

using namespace std;
using i64 = long long;

typedef pair<i64, i64> PII;

int main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);

	int x,i = 0;
	while(1){
		i ++;
		cin >> x;
		if(x == 250){
			cout << i << '\n';
			exit(0);
		}
	}

	return 0;
}

7-4 装睡 - SMU 2024 spring 天梯赛自主训练1 (pintia.cn)

#include <bits/stdc++.h>
#define debug(a) cout<<#a<<"="<<a<<'\n';

using namespace std;
using i64 = long long;

typedef pair<i64, i64> PII;

int main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);

	int n;
	cin >> n;
	for(int i = 0;i < n;i ++){
		string s;
		int x,y;
		cin >> s >> x >> y;
		if(x < 15 || x > 20 || y < 50 || y > 70){
			cout << s << '\n';
		}
	}

	return 0;
}

7-5 矩阵A乘以B - SMU 2024 spring 天梯赛自主训练1 (pintia.cn)

#include <bits/stdc++.h>
#define debug(a) cout<<#a<<"="<<a<<'\n';

using namespace std;
using i64 = long long;

typedef pair<i64, i64> PII;

int main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);

	int ra,ca,rb,cb;

	cin >> ra >> ca;
	vector A(ra,vector<int>(ca));
	for(int i = 0;i < ra;i ++)
		for(int j = 0;j < ca;j ++)
			cin >> A[i][j];
	cin >> rb >> cb;
	vector B(rb,vector<int>(cb));
	for(int i =0;i < rb;i ++)
		for(int j =0;j < cb;j ++)
			cin >> B[i][j];

	if(ca != rb){
		cout << "Error: " << ca << " != " << rb << '\n';
	}else{
		cout << ra << ' ' << cb << '\n';
		for(int i = 0;i < ra;i ++){
			for(int j = 0;j < cb;j ++){
				int res = 0;
				for(int k = 0;k < ca;k ++)
					res += A[i][k] * B[k][j];
				cout << res << " \n"[j == cb - 1];	
			}
		}
	}
	return 0;
}

7-6 稳赢 - SMU 2024 spring 天梯赛自主训练1 (pintia.cn)

#include <bits/stdc++.h>
#define debug(a) cout<<#a<<"="<<a<<'\n';

using namespace std;
using i64 = long long;

typedef pair<i64, i64> PII;

int main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);

	int k, i = 0;
	cin >> k;
	string s;
	cin >> s;
	while(s != "End"){
		i ++;
		if(i % (k + 1) == 0){
			cout << s << '\n';
		}else{
			if(s == "ChuiZi") cout << "Bu\n";
			else if(s == "JianDao") cout << "ChuiZi\n";
			else cout << "JianDao\n";
		}
		cin >> s;
	}

	return 0;
}

7-7 整除光棍 - SMU 2024 spring 天梯赛自主训练1 (pintia.cn)

C++暴力过不了,Python可以;

维护一个全为1的字段以及其位数,每次记得取模;

#include <bits/stdc++.h>
#define debug(a) cout<<#a<<"="<<a<<'\n';

using namespace std;
using i64 = long long;

typedef pair<i64, i64> PII;

int main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);

	int x;
    cin >> x;
    int num = 1,cnt = 1;
    while(num < x){
        num *= 10, num ++;
        cnt ++;
    }

    while(1){
        cout << num / x;
        num %= x;
        if(!num){
            break;
        }
        num *= 10;
        num ++;
        cnt ++;
    }
    cout << ' ' << cnt << '\n';

	return 0;
}

7-8 阅览室 - SMU 2024 spring 天梯赛自主训练1 (pintia.cn)

测试点1,一本书多次借走,以最后一次时间为准,一本书多次返还,以第一次时间为准;

测试点3,平均阅读时间四舍五入;

#include <bits/stdc++.h>
#define debug(a) cout<<#a<<"="<<a<<'\n';

using namespace std;
using i64 = long long;

typedef pair<i64, i64> PII;

struct Book{
    bool f = false;
    int st,ed;
};

int main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);

	int n;
    cin >> n;
    for(int i = 0;i < n;i ++){
        vector<Book> Bu(1010);
        int shu,h,m,sum = 0,num = 0,now = 0;
        char key,op;
        cin >> shu >> key >> h >> op >> m;
        while(shu){
            now = h * 60  + m;
            if(key == 'E' && Bu[shu].f){
                num ++,sum += now - Bu[shu].st;
                Bu[shu].f = false;
            }else if(key == 'S'){
                Bu[shu].f = true;
                Bu[shu].st = max(now,Bu[shu].st);
            }
            cin >> shu >> key >> h >> op >> m;
        }
        cout << num << ' ' << (num ? round(sum*1.0/num) : 0) << '\n';
    }

	return 0;
}

7-9 点赞狂魔 - SMU 2024 spring 天梯赛自主训练1 (pintia.cn)

排序;

#include <bits/stdc++.h>
#define debug(a) cout<<#a<<"="<<a<<'\n';

using namespace std;
using i64 = long long;

typedef pair<i64, i64> PII;

int main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);

	int n;
	cin >> n;
	map<string,set<int>> Name;
	vector<string> ans(n);
	map<string,double> P;
	for(int i = 0;i < n;i ++){
		int k;
		string s;
		cin >> s >> k;
		ans[i] = s;
		for(int j = 0;j < k;j ++){
			int f;
			cin >> f;
			Name[s].insert(f);
		}
		int p = Name[s].size();
		P[s] = 1.0 * k / p ;
	}

	sort(ans.begin(), ans.end(),[&](string a,string b){
		if(Name[a].size() == Name[b].size()) return P[a] < P[b];
		return Name[a].size() > Name[b].size();
	});

	for(int i = 0;i< 3;i++){
		if(i >= ans.size()) cout << "-";
		else cout << ans[i] ;
		cout << " \n"[i == 2];
	}

	return 0;
}

7-10 重排链表 - SMU 2024 spring 天梯赛自主训练1 (pintia.cn)

模拟链表,链表不是按\(Data\)链接的,要按照给出的起始地址得出链表;

链表可能不是一整条链,有多余节点,最后结果得按链表的最终节点数重排;

#include <bits/stdc++.h>
#define debug(a) cout<<#a<<"="<<a<<'\n';

using namespace std;
using i64 = long long;

typedef pair<i64, i64> PII;

int main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);

 	int st,n;
	cin >> st >> n;
	vector<PII> L(n);
	vector<PII> Num(100100);
	for(int i = 0;i < n;i ++){
		int x,a,addr;
		cin >> addr >> a >> x;
		Num[addr] = {a,x}; 
	}

	int cnt = 0;
	while(st != -1){
		L[cnt ++] = {Num[st].first,st};
		st = Num[st].second;
	}

	for(int i = 0,j = cnt - 1;i <= j;i ++, j --){
		if(i == j){
			printf("%05d %d -1\n",L[i].second,L[i].first);
			return 0;
		}
		printf("%05d %d %05d\n", L[j].second,L[j].first,L[i].second);
		printf("%05d %d ",L[i].second,L[i].first);
		if(i == j - 1) printf("-1\n");
		else printf("%05d\n",L[j - 1].second);
	}

	return 0;
}

7-11 图着色问题 - SMU 2024 spring 天梯赛自主训练1 (pintia.cn)

所着色一定为\(k\)种;

dfs判断每个点周围是否合法;

#include <bits/stdc++.h>
#define debug(a) cout<<#a<<"="<<a<<'\n';

using namespace std;
using i64 = long long;

typedef pair<i64, i64> PII;

int main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);

	int n, m, k;
	cin >> n >> m >> k;
	vector g(n + 1, vector<int>());
	for (int i = 0; i < m; i ++) {
		int u, v;
		cin >> u >> v;
		g[u].push_back(v);
		g[v].push_back(u);
	}

	vector<int> color(n + 1);
	vector<bool> vis(n + 1);

	bool ok = true;

	auto solve = [&](auto self, int u, int fa, int x) -> void{
		vis[u] = true;
		for (auto v : g[u]) {
			if (color[v] == x) ok = false;
			if (v == fa) continue;
			if (vis[v]) continue;
			self(self, v, u, color[v]);
		}
	};

	int Case;
	cin >> Case;
	while (Case--) {
		ok = true;
		set<int> ck;
		for (int i = 1; i <= n; i ++) {
			cin >> color[i];
			ck.insert(color[i]);
		}
		for (int i = 1; i <= n; i ++)
			solve(solve, i, 0, -1);
		if (ck.size() != k) ok = false;
		cout << (ok ? "Yes" : "No") << '\n';
		vector<bool>(n + 1).swap(vis);
	}

	return 0;
}

7-12 部落 - SMU 2024 spring 天梯赛自主训练1 (pintia.cn)

并查集;

#include <bits/stdc++.h>
#define debug(a) cout<<#a<<"="<<a<<'\n';

using namespace std;
using i64 = long long;

typedef pair<i64, i64> PII;

int main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);

	int n;
	cin >> n;
	set<int> people;
	vector<int> fa(10010);
	iota(fa.begin(),fa.end(),0);

	auto find = [&](auto self,int x)->int{
		return fa[x] == x ? x : fa[x] = self(self,fa[x]);
	};

	for(int i = 0;i < n;i ++){
		int k,one,u,v;
		cin >> k >> one;
		people.insert(one);
		u = find(find,one);
		for(int j = 1;j < k;j ++){
			int x;
			cin >> x;
			people.insert(x);
			v = find(find,x);
			if(u != v){
				fa[v] = u;
			}
		}
	}

	int All = people.size(), Num = 0;
	for(int i = 1;i <= All;i ++)
		if(find(find,i) == i) Num ++;

	cout << All << ' ' << Num << '\n';

	int m;
	cin >> m;
	while(m --){
		int u,v;
		cin >> u >> v;
		u = find(find,u);
		v = find(find,v);
		if(u != v) cout << "N\n";
		else cout << "Y\n";
	}

	return 0;
}