【7-9 有重复的数据I (20 分)】【此题卡输入,需要自己写个输入挂】
参考一个博客的输入挂,先挂在此处,以备以后使用。
import java.io.*;
import java.util.*;
import java.math.*;
public class Main
{
public static void main(String[] args)
{
InputReader in = new InputReader();
PrintWriter out = new PrintWriter(System.out);
out.close();
}
}
class InputReader
{
BufferedReader buf;
StringTokenizer tok;
InputReader()
{
buf = new BufferedReader(new InputStreamReader(System.in));
}
boolean hasNext()
{
while(tok == null || !tok.hasMoreElements())
{
try
{
tok = new StringTokenizer(buf.readLine());
}
catch(Exception e)
{
return false;
}
}
return true;
}
String next()
{
if(hasNext()) return tok.nextToken();
return null;
}
int nextInt()
{
return Integer.parseInt(next());
}
long nextLong()
{
return Long.parseLong(next());
}
double nextDouble()
{
return Double.parseDouble(next());
}
BigInteger nextBigInteger()
{
return new BigInteger(next());
}
BigDecimal nextBigDecimal()
{
return new BigDecimal(next());
}
}
正确代码:
import java.io.*;
import java.util.*;
import java.math.*;
public class Main{
public static void main(String[] args) {
InputReader in = new InputReader();
PrintWriter out = new PrintWriter(System.out);
final int maxn = 100000+10;
int[] vis = new int[maxn];
int n = in.nextInt(), num, flag = 0;
for(int i = 0; i < n; i++) {
num = in.nextInt();
if(vis[num] == 1)
flag = 1;
vis[num] = 1;
}
if(flag == 0)
out.println("NO");
else
out.println("YES");
out.close();
}
}
class InputReader{
BufferedReader buf;
StringTokenizer tok;
InputReader(){
buf = new BufferedReader(new InputStreamReader(System.in));
}
boolean hasNext() {
while(tok == null || !tok.hasMoreElements()) {
try {
tok = new StringTokenizer(buf.readLine());
}
catch(Exception e) {
return false;
}
}
return true;
}
String next() {
if(hasNext()) {
return tok.nextToken();
}
return null;
}
int nextInt() {
return Integer.parseInt(next());
}
long nextLong() {
return Long.parseLong(next());
}
double nextDouble() {
return Double.parseDouble(next());
}
BigInteger nextBigInteger() {
return new BigInteger(next());
}
BigDecimal nextBigDecimal() {
return new BigDecimal(next());
}
}