Leetcode: Integer to Roman

Given an integer, convert it to a roman numeral.

Input is guaranteed to be within the range from 1 to 3999.

分析:这道题参考leetcode.pdf的解法,代码简洁,处理的巧妙。值得借鉴的几点如下:

(1)将1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1作为基数,从而不用单独处理900,400,90,40,9,4等特殊的情况。

(2)从大的基数开始计算,更简单,因为底数只有13个且最大值为3999,此种方法是可行的。

class Solution {
public:
    string intToRoman(int num) {
        int radix[] = {1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1};
        string symbol[] = {"M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"};
        string result;
        
        for(int i = 0; num > 0; i++){
            int count = num/radix[i];
            num %= radix[i];
            while(count > 0){
                result += symbol[i];
                count--;
            }
        }
        return result;
    }
};

 

posted on 2014-12-09 20:26  Ryan-Xing  阅读(87)  评论(0编辑  收藏  举报