Sort List

Sort a linked list in O(n log n) time using constant space complexity.

分析:merge sort。

class Solution {
public:
    ListNode *sortList(ListNode *head) {
        if(head == NULL || head->next == NULL) return head;
        int len = 0;
        for(ListNode * p = head; p; p = p->next)
            len++;
        
        return mergeSort(head, len);
    }
    
    ListNode * mergeSort(ListNode * head, int l){
        if(l == 0) return NULL;
        if(l == 1) return head;
        
        int l_len = l/2;
        int r_len = l - l_len;
        
        ListNode * p = head;
        for(int i = 0; i < l_len -1; i++)
            p = p->next;
        ListNode * r_head = p->next;
        p->next = NULL;
        
        ListNode * l_list = mergeSort(head, l_len);
        ListNode * r_list = mergeSort(r_head, r_len);
        
        return merge(l_list, r_list);
    }
    
    ListNode * merge(ListNode * left, ListNode * right){
        ListNode * dummy = new ListNode(-1);
        ListNode * p = dummy;
        while(left || right){
            int lv = left?left->val:INT_MAX;
            int rv = right?right->val:INT_MAX;
            
            if(lv <= rv){
                p->next = left;
                left = left->next;
            }else{
                p->next = right;
                right = right->next;
            }
            p = p->next;
        }
        return dummy->next;
    }
};

 

posted on 2014-11-16 15:23  Ryan-Xing  阅读(197)  评论(0编辑  收藏  举报