show me bug

比较版本号 前者大返回1 后者大返回-1 两者一样大返回0

#include <iostream>
#include<string>

using namespace std;
int compare(string A,string B)
{
    int count_A = 0;
    int count_B = 0;

    while( count_A < A.size() || count_B < B.size())
    {
        int A_version = 0;
        int B_version = 0;
        //获取A的第一段版本号
        while(A[count_A] != '.'&& count_A < A.length())
        {
            A_version = A_version * 10;
            A_version += A[count_A++] - '0';
        }
        if(count_A < A.size())
        count_A ++;
        //获取B的版本号
        while(B[count_B] != '.'&& count_B <B.length())
        {
            B_version = B_version * 10;
            B_version += B[count_B++]- '0';
        }
        if(count_B < B.size()-1)
        count_B ++;
        //判断版本号如果不同就return
        if(A_version > B_version)
        {
            return 1;
        }
        else if(A_version < B_version)
        {
            return -1;
        }

    }

    if(count_A < A.length() - 1)//A没有访问到结尾
    {
        return 1;
    }
    else if(count_B < B.length() - 1)//B
    {
        return -1;
    }
    else//版本号相同
    {
        return 0;
    }
}

bug留给过去 ac留给明天~

有些遗憾 但已经过去

未来加油