HDU - 3068 最长回文(manacher)

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3068

求最长回文串,manacher算法。具体可以看转载的blog,代码如下:

#include <iostream>
#include <cstdio>
#include <string>
#include <cstring>
#include <algorithm>
using namespace std;

char line[220020],s[220020];
int Mp[110010*2];

void Manacher(int len){
    int l = 0;
    s[l++] = '$';
    s[l++] = '#';
    for(int i = 0;i < len;i ++){
        s[l++] = line[i];
        s[l++] = '#';
    }

    int id = 0, mx = 0;
    for(int i = 1;i < l;i ++){
        Mp[i] = mx > i ? min(Mp[2*id-i],mx-i) : 1;
        while(s[i + Mp[i]] == s[i - Mp[i]])   Mp[i]++;
        if(i + Mp[i] > mx){
            mx = i+Mp[i];
            id = i;
        }
    }
}

int main()
{
    while(scanf("%s",&line) != EOF){
        //memset(Mp,0,sizeof(Mp));

        int ans = 0;
        int le = strlen(line);
        Manacher(le);

        for(int i = 0;i < le*2+2;i ++)
            ans = max(ans,Mp[i] - 1);
        cout<<ans<<endl;
    }
    return 0;
}



 

posted on 2016-05-20 00:00  Jstyle  阅读(122)  评论(0编辑  收藏  举报

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