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[LeetCode] 206. Reverse Linked List_Easy tag: Linked List

2019-04-30 03:14  Johnson_强生仔仔  阅读(209)  评论(0编辑  收藏  举报

Reverse a singly linked list.

Example:

Input: 1->2->3->4->5->NULL
Output: 5->4->3->2->1->NULL

Follow up:

A linked list can be reversed either iteratively or recursively. Could you implement both?

 

很基本的一道换顺序的题目,先建一个pre 指针,设为None,然后将head.next 存到temp node中,然后将head.next 指针指向pre,接着再将pre和head都依次后移一位。

 

Code:

1) Basic, using temp node

class ListNode:
    def __init__(self, x):
        self.val = x
        self.next = None

class Solution:
    def reverseList(self, head):
        pre = None
        while head:
            temp = head.next
            head.next = pre
            pre = head
            head = temp
        return pre

 

2) 利用python可以多重赋值

class Solution:
    def reverseList(self, head):
        pre = None
        while head:
            head.next, pre, head = pre, head, head.next
        return pre